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Check if object is null and return null
2019 Community Moderator Electionhow to check if limit is approaching in my triggerRunning a child query on Person AccountsWhat reasons would the id in URL be null?deserializing JSON returns a null objectReturn SOQL for current record on Visualforce EmailBest Practices : Page Reference method return nullSOQL Select in test setup?Check isEmpty OR Catch ListException?Ajax REST Tooling Queries Return Null SymbolTable?“Attempt to de-reference a null object” on VF page
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
asked 55 mins ago
ebarebar
132
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
asked 55 mins ago
ebarebar
132
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
asked 55 mins ago
ebarebar
132
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
apex visualforce visualforce-component
asked 55 mins ago
ebarebar
132
asked 55 mins ago
ebarebar
132
asked 55 mins ago
ebarebar
132
asked 55 mins ago
ebarebar
132
asked 55 mins ago
ebarebar
132
132
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 52 mins ago
Keith CKeith C
96.1k1094212
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
21 mins ago
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 51 mins ago
Phil WPhil W
471210
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 52 mins ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 52 mins ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 52 mins ago
Keith CKeith C
96.1k1094212
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 52 mins ago
Keith CKeith C
96.1k1094212
answered 52 mins ago
Keith CKeith C
96.1k1094212
answered 52 mins ago
Keith CKeith C
96.1k1094212
answered 52 mins ago
Keith CKeith C
96.1k1094212
96.1k1094212
add a comment |
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
21 mins ago
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
21 mins ago
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
answered 51 mins ago
sfdcfoxsfdcfox
260k12205450
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
21 mins ago
add a comment |
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
21 mins ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
21 mins ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
21 mins ago
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 51 mins ago
Phil WPhil W
471210
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 51 mins ago
Phil WPhil W
471210
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 51 mins ago
Phil WPhil W
471210
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 51 mins ago
Phil WPhil W
471210
answered 51 mins ago
Phil WPhil W
471210
answered 51 mins ago
Phil WPhil W
471210
answered 51 mins ago
Phil WPhil W
471210
471210
add a comment |
add a comment |
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