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How to color a curve
How to Open Kernel?RDPStruct.exe: what is it and why are there so many?webMathematica evaluation gives unexpected results when imported dynamicallyFrameTicks in BarChartManipulate on Mathematica OnlineHow to use Mathematica Online?Use FIT to calculate regression line from two sets of dataRegression Line in Mathematica using FIT functionPlotting imaginary zeros of a polynomialMathematica online: How to evaluate initialization cells (only)
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]
plotting
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
asked 3 hours ago
Sara yaqobSara yaqob
134
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]
plotting
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
asked 3 hours ago
Sara yaqobSara yaqob
134
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]
plotting
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
asked 3 hours ago
Sara yaqobSara yaqob
134
$endgroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]
plotting
plotting
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
asked 3 hours ago
Sara yaqobSara yaqob
134
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
asked 3 hours ago
Sara yaqobSara yaqob
134
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
edited 10 mins ago
J. M. is slightly pensive♦
98.4k10307466
98.4k10307466
asked 3 hours ago
Sara yaqobSara yaqob
134
asked 3 hours ago
Sara yaqobSara yaqob
134
asked 3 hours ago
Sara yaqobSara yaqob
134
134
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]
answered 3 hours ago
XminerXminer
19918
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
3 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]
Both plotted together
Show[c, R]
answered 3 hours ago
mjwmjw
9679
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
3 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
3 hours ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]
answered 3 hours ago
XminerXminer
19918
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
3 hours ago
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]
answered 3 hours ago
XminerXminer
19918
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
3 hours ago
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]
answered 3 hours ago
XminerXminer
19918
$endgroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]
answered 3 hours ago
XminerXminer
19918
answered 3 hours ago
XminerXminer
19918
answered 3 hours ago
XminerXminer
19918
answered 3 hours ago
XminerXminer
19918
19918
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
3 hours ago
add a comment |
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
3 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]
Both plotted together
Show[c, R]
answered 3 hours ago
mjwmjw
9679
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
3 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
3 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]
Both plotted together
Show[c, R]
answered 3 hours ago
mjwmjw
9679
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
3 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
3 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]
Both plotted together
Show[c, R]
answered 3 hours ago
mjwmjw
9679
$endgroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]
Both plotted together
Show[c, R]
answered 3 hours ago
mjwmjw
9679
edited 3 hours ago
answered 3 hours ago
mjwmjw
9679
answered 3 hours ago
mjwmjw
9679
answered 3 hours ago
mjwmjw
9679
9679
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
3 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
3 hours ago
add a comment |
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
3 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
3 hours ago
1
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
3 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
3 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
3 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
3 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
3 hours ago
add a comment |
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