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How to color a curve


How to Open Kernel?RDPStruct.exe: what is it and why are there so many?webMathematica evaluation gives unexpected results when imported dynamicallyFrameTicks in BarChartManipulate on Mathematica OnlineHow to use Mathematica Online?Use FIT to calculate regression line from two sets of dataRegression Line in Mathematica using FIT functionPlotting imaginary zeros of a polynomialMathematica online: How to evaluate initialization cells (only)













2












$begingroup$


How does one color the interior of the elongated circular region in the following figure:



ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]





plotting







share|improve this question











$endgroup$
















    2












    $begingroup$


    How does one color the interior of the elongated circular region in the following figure:



    ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]





    plotting







    share|improve this question











    $endgroup$














      2












      2








      2


      0



      $begingroup$


      How does one color the interior of the elongated circular region in the following figure:



      ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]





      plotting







      share|improve this question











      $endgroup$




      How does one color the interior of the elongated circular region in the following figure:



      ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]





      plotting




      plotting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 10 mins ago









      J. M. is slightly pensive♦

      98.4k10307466




      98.4k10307466










      asked 3 hours ago









      Sara yaqobSara yaqob

      134




      134




















          2 Answers
          2






          active

          oldest

          votes


















          1












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$












          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            3 hours ago


















          1












          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$








          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            3 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            3 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago










          Your Answer





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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$












          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            3 hours ago















          1












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$












          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            3 hours ago













          1












          1








          1





          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$



          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 3 hours ago









          XminerXminer

          19918




          19918











          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            3 hours ago
















          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            3 hours ago















          $begingroup$
          But I need only the curve not the surface
          $endgroup$
          – Sara yaqob
          3 hours ago




          $begingroup$
          But I need only the curve not the surface
          $endgroup$
          – Sara yaqob
          3 hours ago











          1












          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$








          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            3 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            3 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago















          1












          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$








          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            3 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            3 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago













          1












          1








          1





          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$



          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 3 hours ago

























          answered 3 hours ago









          mjwmjw

          9679




          9679







          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            3 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            3 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago












          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            3 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            3 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago







          1




          1




          $begingroup$
          Thank you so so much sir. That's what I need.
          $endgroup$
          – Sara yaqob
          3 hours ago




          $begingroup$
          Thank you so so much sir. That's what I need.
          $endgroup$
          – Sara yaqob
          3 hours ago












          $begingroup$
          @Sara, You are welcome!
          $endgroup$
          – mjw
          3 hours ago




          $begingroup$
          @Sara, You are welcome!
          $endgroup$
          – mjw
          3 hours ago












          $begingroup$
          @Sarayaqob you mistakenly accepted my answer
          $endgroup$
          – Xminer
          3 hours ago




          $begingroup$
          @Sarayaqob you mistakenly accepted my answer
          $endgroup$
          – Xminer
          3 hours ago

















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