Why would a new[] expression ever invoke a destructor?About constructors/destructors and new/delete operators in C++ for custom objectsDoes delete call the destructor?Overloading operator delete in a base classWhen is %destructor invoked in BISON?Why should C++ programmers minimize use of 'new'?Why is ::operator new[] necessary when ::operator new is enough?Why am I permitted to declare an object with a deleted destructor?Does delete[] deallocate memory in one shot after invoking destructors?Why are non-placement `new` and `delete` built into the language and not just regular functions?Why deallocation function is not called when object constructor throw in a new expression?
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Why would a new[] expression ever invoke a destructor?
About constructors/destructors and new/delete operators in C++ for custom objectsDoes delete call the destructor?Overloading operator delete in a base classWhen is %destructor invoked in BISON?Why should C++ programmers minimize use of 'new'?Why is ::operator new[] necessary when ::operator new is enough?Why am I permitted to declare an object with a deleted destructor?Does delete[] deallocate memory in one shot after invoking destructors?Why are non-placement `new` and `delete` built into the language and not just regular functions?Why deallocation function is not called when object constructor throw in a new expression?
From the C++17 standard (draft here), [expr.new]:
If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.
Why would new[] invoke a destructor? It's new, after all. It isn't delete.
c++ c++17 new-operator
edited 1 hour ago
Cody Gray♦
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thbthb
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From the C++17 standard (draft here), [expr.new]:
If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.
Why would new[] invoke a destructor? It's new, after all. It isn't delete.
c++ c++17 new-operator
edited 1 hour ago
Cody Gray♦
195k35382470
asked 1 hour ago
thbthb
8,66432355
add a comment |
From the C++17 standard (draft here), [expr.new]:
If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.
Why would new[] invoke a destructor? It's new, after all. It isn't delete.
c++ c++17 new-operator
edited 1 hour ago
Cody Gray♦
195k35382470
asked 1 hour ago
thbthb
8,66432355
From the C++17 standard (draft here), [expr.new]:
If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.
Why would new[] invoke a destructor? It's new, after all. It isn't delete.
c++ c++17 new-operator
c++ c++17 new-operator
edited 1 hour ago
Cody Gray♦
195k35382470
asked 1 hour ago
thbthb
8,66432355
edited 1 hour ago
Cody Gray♦
195k35382470
asked 1 hour ago
thbthb
8,66432355
edited 1 hour ago
Cody Gray♦
195k35382470
edited 1 hour ago
Cody Gray♦
195k35382470
edited 1 hour ago
Cody Gray♦
195k35382470
195k35382470
asked 1 hour ago
thbthb
8,66432355
asked 1 hour ago
thbthb
8,66432355
asked 1 hour ago
thbthb
8,66432355
8,66432355
add a comment |
add a comment |
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If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.
edited 1 hour ago
Sombrero Chicken
24.4k33281
answered 1 hour ago
StoryTellerStoryTeller
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If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.
edited 1 hour ago
Sombrero Chicken
24.4k33281
answered 1 hour ago
StoryTellerStoryTeller
103k12215280
add a comment |
If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.
edited 1 hour ago
Sombrero Chicken
24.4k33281
answered 1 hour ago
StoryTellerStoryTeller
103k12215280
add a comment |
If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.
edited 1 hour ago
Sombrero Chicken
24.4k33281
answered 1 hour ago
StoryTellerStoryTeller
103k12215280
If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.
edited 1 hour ago
Sombrero Chicken
24.4k33281
answered 1 hour ago
StoryTellerStoryTeller
103k12215280
edited 1 hour ago
Sombrero Chicken
24.4k33281
edited 1 hour ago
Sombrero Chicken
24.4k33281
edited 1 hour ago
Sombrero Chicken
24.4k33281
24.4k33281
answered 1 hour ago
StoryTellerStoryTeller
103k12215280
answered 1 hour ago
StoryTellerStoryTeller
103k12215280
answered 1 hour ago
StoryTellerStoryTeller
103k12215280
103k12215280
add a comment |
add a comment |
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