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Escape a backup date in a file name
the slash (/) after a directory name on shell commandsDate time in Linux bashCreate sub-directories and organize files by date from file nameWhat is the difference between a directory name that ends with a slash and one that does not?How do you put date and time in a file name?adding date to beginning of file name using scripttcsh - echo escape code for escapeConvert date in bash shellHow to adjust the Exif timestamp of a photo using the date in its nameshell script to walk folders and sub-folders, convert timestamp to UTC format and export .csv file
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
shell filenames date escape-characters slash
edited 1 hour ago
Gilles
544k12811041621
asked 6 hours ago
tres.14159tres.14159
2612
add a comment |
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
shell filenames date escape-characters slash
edited 1 hour ago
Gilles
544k12811041621
asked 6 hours ago
tres.14159tres.14159
2612
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
6 hours ago
the problem is your use of thedateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
– 0xSheepdog
6 hours ago
add a comment |
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
shell filenames date escape-characters slash
edited 1 hour ago
Gilles
544k12811041621
asked 6 hours ago
tres.14159tres.14159
2612
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
shell filenames date escape-characters slash
shell filenames date escape-characters slash
edited 1 hour ago
Gilles
544k12811041621
asked 6 hours ago
tres.14159tres.14159
2612
edited 1 hour ago
Gilles
544k12811041621
asked 6 hours ago
tres.14159tres.14159
2612
edited 1 hour ago
Gilles
544k12811041621
edited 1 hour ago
Gilles
544k12811041621
edited 1 hour ago
Gilles
544k12811041621
544k12811041621
asked 6 hours ago
tres.14159tres.14159
2612
asked 6 hours ago
tres.14159tres.14159
2612
asked 6 hours ago
tres.14159tres.14159
2612
2612
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
6 hours ago
the problem is your use of thedateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
– 0xSheepdog
6 hours ago
add a comment |
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
6 hours ago
the problem is your use of thedateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
– 0xSheepdog
6 hours ago
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
6 hours ago
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
6 hours ago
the problem is your use of the
date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.– 0xSheepdog
6 hours ago
the problem is your use of the
date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.– 0xSheepdog
6 hours ago
add a comment |
1 Answer
1
active
oldest
votes
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
add a comment |
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1 Answer
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oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
add a comment |
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
add a comment |
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
edited 5 hours ago
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
answered 6 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588946
311k57588946
add a comment |
add a comment |
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You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
6 hours ago
the problem is your use of the
dateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.– 0xSheepdog
6 hours ago