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How to escape string to filename? It is in backup a file append date
Converting a string from a file into a dateHow to append date to backup fileCreate sub-directories and organize files by date from file namecannot create regular file 'filename': File existsHow to append a date to all files in a directory without touching sub-directories via bash scriptadding date to beginning of file name using scriptinserting modified date into filename - 2 casesCan the date command take as argument a date string in a file given by another date command?Set file modification date from date stored as filenameHow to Find and delete File Older than 3 years without scaning on modified date?
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
backup date cp escape-characters
asked 4 hours ago
tres.14159tres.14159
2112
add a comment |
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
backup date cp escape-characters
asked 4 hours ago
tres.14159tres.14159
2112
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
4 hours ago
the problem is your use of thedateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
– 0xSheepdog
4 hours ago
add a comment |
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
backup date cp escape-characters
asked 4 hours ago
tres.14159tres.14159
2112
I have been trying to:
cp file.csv file.$(date +%D).csv
But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.
And I have been trying again to:
cp file.csv file.$(printf "%q" $(date +%D)).csv
But it still fails.
backup date cp escape-characters
backup date cp escape-characters
asked 4 hours ago
tres.14159tres.14159
2112
asked 4 hours ago
tres.14159tres.14159
2112
asked 4 hours ago
tres.14159tres.14159
2112
asked 4 hours ago
tres.14159tres.14159
2112
asked 4 hours ago
tres.14159tres.14159
2112
2112
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
4 hours ago
the problem is your use of thedateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
– 0xSheepdog
4 hours ago
add a comment |
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
4 hours ago
the problem is your use of thedateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
– 0xSheepdog
4 hours ago
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
4 hours ago
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
4 hours ago
the problem is your use of the
date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.– 0xSheepdog
4 hours ago
the problem is your use of the
date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.– 0xSheepdog
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
add a comment |
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
add a comment |
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.
You can use characters that look like / like ⁄ (fraction slash), so you could do:
cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"
But you may run into problems like the file name being rendered differently in locales using a different charset.
My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):
cp file.csv "file.$(date +%Y-%m-%d).csv"
Which with many date implementations you can shorten to:
cp file.csv "file.$(date +%F).csv"
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
edited 3 hours ago
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
answered 4 hours ago
Stéphane ChazelasStéphane Chazelas
311k57588945
311k57588945
add a comment |
add a comment |
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1J6IRTMQpI,YCPO4cZb6 m0fnW,LYS HWnJufim7cgnoVMyC0U cHvtMLEt,6mEY25EbiZ,qPsdIse,84XrwpPzo
You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
– tres.14159
4 hours ago
the problem is your use of the
dateformat using the/character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available fromdate. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.– 0xSheepdog
4 hours ago