Which big number is bigger? Unicorn Meta Zoo #1: Why another podcast? Announcing the arrival of Valued Associate #679: Cesar Manara The PPCG Site design is on its way - help us make it awesome! Sandbox for Proposed ChallengesIs q a quadratic residue of n?Determine if an Array contains something other than 2Does the sum of 2 numbers in the list equal the desired sum?Is this number a factorial?Test if two numbers are equalDo two numbers contain unique powers of 2Do two numbers contain unique factorials?Impossible cube maybeAm I divisible by double the sum of my digits?Check if a string is entirely made of the same substring

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Which big number is bigger?



Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar Manara
The PPCG Site design is on its way - help us make it awesome!
Sandbox for Proposed ChallengesIs q a quadratic residue of n?Determine if an Array contains something other than 2Does the sum of 2 numbers in the list equal the desired sum?Is this number a factorial?Test if two numbers are equalDo two numbers contain unique powers of 2Do two numbers contain unique factorials?Impossible cube maybeAm I divisible by double the sum of my digits?Check if a string is entirely made of the same substring










6












$begingroup$


Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)





code-golf







share|improve this question











$endgroup$







  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    43 mins ago






  • 2




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    42 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    39 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    26 mins ago







  • 2




    $begingroup$
    @Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
    $endgroup$
    – Luis Mendo
    5 mins ago
















6












$begingroup$


Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)





code-golf







share|improve this question











$endgroup$







  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    43 mins ago






  • 2




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    42 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    39 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    26 mins ago







  • 2




    $begingroup$
    @Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
    $endgroup$
    – Luis Mendo
    5 mins ago














6












6








6





$begingroup$


Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)





code-golf







share|improve this question











$endgroup$




Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)
1^(2^3) < 3^(2^1)
3^(6^5) < 5^(20^3)
20^(20^20) > 20^(20^19)
20^(20^20) is not bigger than 20^(20^20)





code-golf




code-golf






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 22 mins ago







Anush

















asked 46 mins ago









AnushAnush

869627




869627







  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    43 mins ago






  • 2




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    42 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    39 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    26 mins ago







  • 2




    $begingroup$
    @Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
    $endgroup$
    – Luis Mendo
    5 mins ago













  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    43 mins ago






  • 2




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    42 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    39 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    26 mins ago







  • 2




    $begingroup$
    @Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
    $endgroup$
    – Luis Mendo
    5 mins ago








1




1




$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
$endgroup$
– Unrelated String
43 mins ago




$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
$endgroup$
– Unrelated String
43 mins ago




2




2




$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
42 mins ago




$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
42 mins ago












$begingroup$
@KevinCruijssen No. They have to be in the order given.
$endgroup$
– Anush
39 mins ago




$begingroup$
@KevinCruijssen No. They have to be in the order given.
$endgroup$
– Anush
39 mins ago












$begingroup$
Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
$endgroup$
– Kevin Cruijssen
26 mins ago





$begingroup$
Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
$endgroup$
– Kevin Cruijssen
26 mins ago





2




2




$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
5 mins ago





$begingroup$
@Anush Imposing a specific order of inputs it not common at all. You should specify that very clearly in the text. By default imput order and format are flexible
$endgroup$
– Luis Mendo
5 mins ago











5 Answers
5






active

oldest

votes


















6












$begingroup$

JavaScript (ES6), 43 bytes



Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.





(a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


Try it online!






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    Eheh we had the same idea... and almost the same byte count :P
    $endgroup$
    – digEmAll
    33 mins ago


















4












$begingroup$


R, 42 bytes





function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


Try it online!






share|improve this answer









$endgroup$




















    3












    $begingroup$


    05AB1E, 11 9 bytes



    εć.²š}P`›


    Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)

    -2 bytes thanks to @Emigna



    Input as [[a1,a2,a3],[b1,b2,b3]].



    Try it online or verify all test cases.



    Explanation:





    ε # Map the (implicit) input-lists to:
     ć # Extract the head; pushing the remainder and head separated to the stack
     .² # Get the logarithm with base 2 of this head
     š # And prepend it back to the remainder
     }P # After the map: take the product of both mapped inner lists
     ` # Push both integers separated to the stack
     › # And check if A is larger than B





    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      You second version can be εć.²š]P`›
      $endgroup$
      – Emigna
      18 mins ago











    • $begingroup$
      @Emigna Ah nice, I was looking at an approach with ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!
      $endgroup$
      – Kevin Cruijssen
      17 mins ago



















    2












    $begingroup$


    05AB1E, 11 bytes



    Uses the method from Arnauld's JS answer



    .²**U.²**X‹


    Try it online!



    2F.²**ˆ}¯`› also works at the same byte count






    share|improve this answer











    $endgroup$












    • $begingroup$
      This doesn't terminate for a1=20, a2=20, a3=20.
      $endgroup$
      – Anush
      37 mins ago






    • 1




      $begingroup$
      @Anush: Seems to terminate in less than a second to me.
      $endgroup$
      – Emigna
      36 mins ago










    • $begingroup$
      you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
      $endgroup$
      – Anush
      35 mins ago










    • $begingroup$
      @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
      $endgroup$
      – Emigna
      34 mins ago






    • 1




      $begingroup$
      @Anush: It is fixed now. Thanks for pointing out my mistake :)
      $endgroup$
      – Emigna
      21 mins ago


















    2












    $begingroup$


    Wolfram Language (Mathematica), 23 bytes



    #2^#3Log@#>#5^#6Log@#4&


    Try it online!






    share|improve this answer











    $endgroup$












    • $begingroup$
      This doesn't terminate for a1=20, a2=20, a3=20.
      $endgroup$
      – Anush
      38 mins ago










    • $begingroup$
      @Anush fixed...
      $endgroup$
      – J42161217
      9 mins ago











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    5 Answers
    5






    active

    oldest

    votes








    5 Answers
    5






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    6












    $begingroup$

    JavaScript (ES6), 43 bytes



    Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.





    (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


    Try it online!






    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      Eheh we had the same idea... and almost the same byte count :P
      $endgroup$
      – digEmAll
      33 mins ago















    6












    $begingroup$

    JavaScript (ES6), 43 bytes



    Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.





    (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


    Try it online!






    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      Eheh we had the same idea... and almost the same byte count :P
      $endgroup$
      – digEmAll
      33 mins ago













    6












    6








    6





    $begingroup$

    JavaScript (ES6), 43 bytes



    Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.





    (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


    Try it online!






    share|improve this answer











    $endgroup$



    JavaScript (ES6), 43 bytes



    Returns $true$ if $a^b^c > d^e^f$, or $false$ otherwise.





    (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


    Try it online!







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 20 mins ago

























    answered 37 mins ago









    ArnauldArnauld

    82.2k798337




    82.2k798337







    • 1




      $begingroup$
      Eheh we had the same idea... and almost the same byte count :P
      $endgroup$
      – digEmAll
      33 mins ago












    • 1




      $begingroup$
      Eheh we had the same idea... and almost the same byte count :P
      $endgroup$
      – digEmAll
      33 mins ago







    1




    1




    $begingroup$
    Eheh we had the same idea... and almost the same byte count :P
    $endgroup$
    – digEmAll
    33 mins ago




    $begingroup$
    Eheh we had the same idea... and almost the same byte count :P
    $endgroup$
    – digEmAll
    33 mins ago











    4












    $begingroup$


    R, 42 bytes





    function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


    Try it online!






    share|improve this answer









    $endgroup$

















      4












      $begingroup$


      R, 42 bytes





      function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


      Try it online!






      share|improve this answer









      $endgroup$















        4












        4








        4





        $begingroup$


        R, 42 bytes





        function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


        Try it online!






        share|improve this answer









        $endgroup$




        R, 42 bytes





        function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


        Try it online!







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 34 mins ago









        digEmAlldigEmAll

        3,664515




        3,664515





















            3












            $begingroup$


            05AB1E, 11 9 bytes



            εć.²š}P`›


            Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)

            -2 bytes thanks to @Emigna



            Input as [[a1,a2,a3],[b1,b2,b3]].



            Try it online or verify all test cases.



            Explanation:





            ε # Map the (implicit) input-lists to:
             ć # Extract the head; pushing the remainder and head separated to the stack
             .² # Get the logarithm with base 2 of this head
             š # And prepend it back to the remainder
             }P # After the map: take the product of both mapped inner lists
             ` # Push both integers separated to the stack
             › # And check if A is larger than B





            share|improve this answer











            $endgroup$








            • 1




              $begingroup$
              You second version can be εć.²š]P`›
              $endgroup$
              – Emigna
              18 mins ago











            • $begingroup$
              @Emigna Ah nice, I was looking at an approach with ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!
              $endgroup$
              – Kevin Cruijssen
              17 mins ago
















            3












            $begingroup$


            05AB1E, 11 9 bytes



            εć.²š}P`›


            Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)

            -2 bytes thanks to @Emigna



            Input as [[a1,a2,a3],[b1,b2,b3]].



            Try it online or verify all test cases.



            Explanation:





            ε # Map the (implicit) input-lists to:
             ć # Extract the head; pushing the remainder and head separated to the stack
             .² # Get the logarithm with base 2 of this head
             š # And prepend it back to the remainder
             }P # After the map: take the product of both mapped inner lists
             ` # Push both integers separated to the stack
             › # And check if A is larger than B





            share|improve this answer











            $endgroup$








            • 1




              $begingroup$
              You second version can be εć.²š]P`›
              $endgroup$
              – Emigna
              18 mins ago











            • $begingroup$
              @Emigna Ah nice, I was looking at an approach with ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!
              $endgroup$
              – Kevin Cruijssen
              17 mins ago














            3












            3








            3





            $begingroup$


            05AB1E, 11 9 bytes



            εć.²š}P`›


            Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)

            -2 bytes thanks to @Emigna



            Input as [[a1,a2,a3],[b1,b2,b3]].



            Try it online or verify all test cases.



            Explanation:





            ε # Map the (implicit) input-lists to:
             ć # Extract the head; pushing the remainder and head separated to the stack
             .² # Get the logarithm with base 2 of this head
             š # And prepend it back to the remainder
             }P # After the map: take the product of both mapped inner lists
             ` # Push both integers separated to the stack
             › # And check if A is larger than B





            share|improve this answer











            $endgroup$




            05AB1E, 11 9 bytes



            εć.²š}P`›


            Port of @Arnauld's JavaScript and @digEmAll's R approaches (I saw them post around the same time)

            -2 bytes thanks to @Emigna



            Input as [[a1,a2,a3],[b1,b2,b3]].



            Try it online or verify all test cases.



            Explanation:





            ε # Map the (implicit) input-lists to:
             ć # Extract the head; pushing the remainder and head separated to the stack
             .² # Get the logarithm with base 2 of this head
             š # And prepend it back to the remainder
             }P # After the map: take the product of both mapped inner lists
             ` # Push both integers separated to the stack
             › # And check if A is larger than B






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 10 mins ago

























            answered 22 mins ago









            Kevin CruijssenKevin Cruijssen

            43.5k573222




            43.5k573222







            • 1




              $begingroup$
              You second version can be εć.²š]P`›
              $endgroup$
              – Emigna
              18 mins ago











            • $begingroup$
              @Emigna Ah nice, I was looking at an approach with ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!
              $endgroup$
              – Kevin Cruijssen
              17 mins ago













            • 1




              $begingroup$
              You second version can be εć.²š]P`›
              $endgroup$
              – Emigna
              18 mins ago











            • $begingroup$
              @Emigna Ah nice, I was looking at an approach with ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!
              $endgroup$
              – Kevin Cruijssen
              17 mins ago








            1




            1




            $begingroup$
            You second version can be εć.²š]P`›
            $endgroup$
            – Emigna
            18 mins ago





            $begingroup$
            You second version can be εć.²š]P`›
            $endgroup$
            – Emigna
            18 mins ago













            $begingroup$
            @Emigna Ah nice, I was looking at an approach with ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!
            $endgroup$
            – Kevin Cruijssen
            17 mins ago





            $begingroup$
            @Emigna Ah nice, I was looking at an approach with ć, but completely forgot about using š (not sure why now that I see it, haha). Thanks!
            $endgroup$
            – Kevin Cruijssen
            17 mins ago












            2












            $begingroup$


            05AB1E, 11 bytes



            Uses the method from Arnauld's JS answer



            .²**U.²**X‹


            Try it online!



            2F.²**ˆ}¯`› also works at the same byte count






            share|improve this answer











            $endgroup$












            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              37 mins ago






            • 1




              $begingroup$
              @Anush: Seems to terminate in less than a second to me.
              $endgroup$
              – Emigna
              36 mins ago










            • $begingroup$
              you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
              $endgroup$
              – Anush
              35 mins ago










            • $begingroup$
              @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
              $endgroup$
              – Emigna
              34 mins ago






            • 1




              $begingroup$
              @Anush: It is fixed now. Thanks for pointing out my mistake :)
              $endgroup$
              – Emigna
              21 mins ago















            2












            $begingroup$


            05AB1E, 11 bytes



            Uses the method from Arnauld's JS answer



            .²**U.²**X‹


            Try it online!



            2F.²**ˆ}¯`› also works at the same byte count






            share|improve this answer











            $endgroup$












            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              37 mins ago






            • 1




              $begingroup$
              @Anush: Seems to terminate in less than a second to me.
              $endgroup$
              – Emigna
              36 mins ago










            • $begingroup$
              you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
              $endgroup$
              – Anush
              35 mins ago










            • $begingroup$
              @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
              $endgroup$
              – Emigna
              34 mins ago






            • 1




              $begingroup$
              @Anush: It is fixed now. Thanks for pointing out my mistake :)
              $endgroup$
              – Emigna
              21 mins ago













            2












            2








            2





            $begingroup$


            05AB1E, 11 bytes



            Uses the method from Arnauld's JS answer



            .²**U.²**X‹


            Try it online!



            2F.²**ˆ}¯`› also works at the same byte count






            share|improve this answer











            $endgroup$




            05AB1E, 11 bytes



            Uses the method from Arnauld's JS answer



            .²**U.²**X‹


            Try it online!



            2F.²**ˆ}¯`› also works at the same byte count







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 24 mins ago

























            answered 40 mins ago









            EmignaEmigna

            48.3k434147




            48.3k434147











            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              37 mins ago






            • 1




              $begingroup$
              @Anush: Seems to terminate in less than a second to me.
              $endgroup$
              – Emigna
              36 mins ago










            • $begingroup$
              you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
              $endgroup$
              – Anush
              35 mins ago










            • $begingroup$
              @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
              $endgroup$
              – Emigna
              34 mins ago






            • 1




              $begingroup$
              @Anush: It is fixed now. Thanks for pointing out my mistake :)
              $endgroup$
              – Emigna
              21 mins ago
















            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              37 mins ago






            • 1




              $begingroup$
              @Anush: Seems to terminate in less than a second to me.
              $endgroup$
              – Emigna
              36 mins ago










            • $begingroup$
              you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
              $endgroup$
              – Anush
              35 mins ago










            • $begingroup$
              @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
              $endgroup$
              – Emigna
              34 mins ago






            • 1




              $begingroup$
              @Anush: It is fixed now. Thanks for pointing out my mistake :)
              $endgroup$
              – Emigna
              21 mins ago















            $begingroup$
            This doesn't terminate for a1=20, a2=20, a3=20.
            $endgroup$
            – Anush
            37 mins ago




            $begingroup$
            This doesn't terminate for a1=20, a2=20, a3=20.
            $endgroup$
            – Anush
            37 mins ago




            1




            1




            $begingroup$
            @Anush: Seems to terminate in less than a second to me.
            $endgroup$
            – Emigna
            36 mins ago




            $begingroup$
            @Anush: Seems to terminate in less than a second to me.
            $endgroup$
            – Emigna
            36 mins ago












            $begingroup$
            you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
            $endgroup$
            – Anush
            35 mins ago




            $begingroup$
            you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
            $endgroup$
            – Anush
            35 mins ago












            $begingroup$
            @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
            $endgroup$
            – Emigna
            34 mins ago




            $begingroup$
            @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
            $endgroup$
            – Emigna
            34 mins ago




            1




            1




            $begingroup$
            @Anush: It is fixed now. Thanks for pointing out my mistake :)
            $endgroup$
            – Emigna
            21 mins ago




            $begingroup$
            @Anush: It is fixed now. Thanks for pointing out my mistake :)
            $endgroup$
            – Emigna
            21 mins ago











            2












            $begingroup$


            Wolfram Language (Mathematica), 23 bytes



            #2^#3Log@#>#5^#6Log@#4&


            Try it online!






            share|improve this answer











            $endgroup$












            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              38 mins ago










            • $begingroup$
              @Anush fixed...
              $endgroup$
              – J42161217
              9 mins ago















            2












            $begingroup$


            Wolfram Language (Mathematica), 23 bytes



            #2^#3Log@#>#5^#6Log@#4&


            Try it online!






            share|improve this answer











            $endgroup$












            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              38 mins ago










            • $begingroup$
              @Anush fixed...
              $endgroup$
              – J42161217
              9 mins ago













            2












            2








            2





            $begingroup$


            Wolfram Language (Mathematica), 23 bytes



            #2^#3Log@#>#5^#6Log@#4&


            Try it online!






            share|improve this answer











            $endgroup$




            Wolfram Language (Mathematica), 23 bytes



            #2^#3Log@#>#5^#6Log@#4&


            Try it online!







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 10 mins ago

























            answered 41 mins ago









            J42161217J42161217

            14.4k21354




            14.4k21354











            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              38 mins ago










            • $begingroup$
              @Anush fixed...
              $endgroup$
              – J42161217
              9 mins ago
















            • $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              38 mins ago










            • $begingroup$
              @Anush fixed...
              $endgroup$
              – J42161217
              9 mins ago















            $begingroup$
            This doesn't terminate for a1=20, a2=20, a3=20.
            $endgroup$
            – Anush
            38 mins ago




            $begingroup$
            This doesn't terminate for a1=20, a2=20, a3=20.
            $endgroup$
            – Anush
            38 mins ago












            $begingroup$
            @Anush fixed...
            $endgroup$
            – J42161217
            9 mins ago




            $begingroup$
            @Anush fixed...
            $endgroup$
            – J42161217
            9 mins ago

















            draft saved

            draft discarded
















































            If this is an answer to a challenge…



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            JFtp0nIoq,mVpqNXVl6Z5mgKYB,rUw DNuZyy,B8WKR3HaxhNibAwD
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