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Request info on 12/48v PSU
Does the pin order matter for an EPS12V 8-pin +12V connector?DC PSU questions (+/- voltages, home-built ammeter)Current flow priorities in PSU / PSU reviewConnecting potentiometer to an ATX PSUATX power supply only 0.1A from 12V rail?Split External 5V PSU 4 waysNeed help interpreting a printer PS labelCan AC floating ground be used as a common ground to a DC circuit?Has Anyone Ever Gotten a Delta DPS-400AB-5 A PSU to Work Standalone?XBOX 360 PSU for walkie-talkie chargers
$begingroup$
I've got a power supply unit from a defunct/decommissioned Satellite Internet setup, and I'm hoping to get clarification on some of the markings on the label.
In the following picture, there's four pin numbers, followed underneath of pins 1 and 2 both volts and max amps, and pins 3 and 4 simply "RETURN".
My question is whether I'm reading the label correctly. (Technically, I've got a few questions here).
Does max(A) under pin 1 mean that at 12v I've got 2.99A available, and at the 48v pin, I've got a max of 0.82A?
Also, when pins 3 and 4 are reflected as return, I'm assuming that means ground, yes?
I'll summarize my questions here to consolidate:
1) is pin 1 +12v @ 2.99A?
2) is pin 2 +48v @ 0.82A?
3) are pins 3 and 4 ground pins, that could (and potentially should) be wired together if both pin 1 and 2 are in use simultaneously?
Here's the pic of the label of the power supply in question:
power-supply
asked 5 hours ago
steviebstevieb
1265
$endgroup$
add a comment |
$begingroup$
I've got a power supply unit from a defunct/decommissioned Satellite Internet setup, and I'm hoping to get clarification on some of the markings on the label.
In the following picture, there's four pin numbers, followed underneath of pins 1 and 2 both volts and max amps, and pins 3 and 4 simply "RETURN".
My question is whether I'm reading the label correctly. (Technically, I've got a few questions here).
Does max(A) under pin 1 mean that at 12v I've got 2.99A available, and at the 48v pin, I've got a max of 0.82A?
Also, when pins 3 and 4 are reflected as return, I'm assuming that means ground, yes?
I'll summarize my questions here to consolidate:
1) is pin 1 +12v @ 2.99A?
2) is pin 2 +48v @ 0.82A?
3) are pins 3 and 4 ground pins, that could (and potentially should) be wired together if both pin 1 and 2 are in use simultaneously?
Here's the pic of the label of the power supply in question:
power-supply
asked 5 hours ago
steviebstevieb
1265
$endgroup$
2
$begingroup$
To me it seems your interpretation of the label is correct.
$endgroup$
– K. S.
5 hours ago
1
$begingroup$
@K.S. I thought so. It appears obvious, but I thought I'd ask the experts.
$endgroup$
– stevieb
5 hours ago
add a comment |
$begingroup$
I've got a power supply unit from a defunct/decommissioned Satellite Internet setup, and I'm hoping to get clarification on some of the markings on the label.
In the following picture, there's four pin numbers, followed underneath of pins 1 and 2 both volts and max amps, and pins 3 and 4 simply "RETURN".
My question is whether I'm reading the label correctly. (Technically, I've got a few questions here).
Does max(A) under pin 1 mean that at 12v I've got 2.99A available, and at the 48v pin, I've got a max of 0.82A?
Also, when pins 3 and 4 are reflected as return, I'm assuming that means ground, yes?
I'll summarize my questions here to consolidate:
1) is pin 1 +12v @ 2.99A?
2) is pin 2 +48v @ 0.82A?
3) are pins 3 and 4 ground pins, that could (and potentially should) be wired together if both pin 1 and 2 are in use simultaneously?
Here's the pic of the label of the power supply in question:
power-supply
asked 5 hours ago
steviebstevieb
1265
$endgroup$
I've got a power supply unit from a defunct/decommissioned Satellite Internet setup, and I'm hoping to get clarification on some of the markings on the label.
In the following picture, there's four pin numbers, followed underneath of pins 1 and 2 both volts and max amps, and pins 3 and 4 simply "RETURN".
My question is whether I'm reading the label correctly. (Technically, I've got a few questions here).
Does max(A) under pin 1 mean that at 12v I've got 2.99A available, and at the 48v pin, I've got a max of 0.82A?
Also, when pins 3 and 4 are reflected as return, I'm assuming that means ground, yes?
I'll summarize my questions here to consolidate:
1) is pin 1 +12v @ 2.99A?
2) is pin 2 +48v @ 0.82A?
3) are pins 3 and 4 ground pins, that could (and potentially should) be wired together if both pin 1 and 2 are in use simultaneously?
Here's the pic of the label of the power supply in question:
power-supply
power-supply
asked 5 hours ago
steviebstevieb
1265
asked 5 hours ago
steviebstevieb
1265
asked 5 hours ago
steviebstevieb
1265
asked 5 hours ago
steviebstevieb
1265
asked 5 hours ago
steviebstevieb
1265
1265
2
$begingroup$
To me it seems your interpretation of the label is correct.
$endgroup$
– K. S.
5 hours ago
1
$begingroup$
@K.S. I thought so. It appears obvious, but I thought I'd ask the experts.
$endgroup$
– stevieb
5 hours ago
add a comment |
2
$begingroup$
To me it seems your interpretation of the label is correct.
$endgroup$
– K. S.
5 hours ago
1
$begingroup$
@K.S. I thought so. It appears obvious, but I thought I'd ask the experts.
$endgroup$
– stevieb
5 hours ago
2
2
$begingroup$
To me it seems your interpretation of the label is correct.
$endgroup$
– K. S.
5 hours ago
$begingroup$
To me it seems your interpretation of the label is correct.
$endgroup$
– K. S.
5 hours ago
1
1
$begingroup$
@K.S. I thought so. It appears obvious, but I thought I'd ask the experts.
$endgroup$
– stevieb
5 hours ago
$begingroup$
@K.S. I thought so. It appears obvious, but I thought I'd ask the experts.
$endgroup$
– stevieb
5 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Yes, your interpretation of the label is correct as far as I can tell.
Note also that $12 mathrmV·2.99 mathrmA + 48 mathrmV·0.82 mathrmA = 75.24 mathrmW$, in agreement with the 75 W power rating. This, combined with how simple this interpretation of the markings is, is sufficient evidence for me to say with confidence that you are correct.
simulate this circuit – Schematic created using CircuitLab
edited 3 hours ago
Jasen
11.4k1531
answered 4 hours ago
HearthHearth
4,6601137
$endgroup$
add a comment |
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1 Answer
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1 Answer
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oldest
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$begingroup$
Yes, your interpretation of the label is correct as far as I can tell.
Note also that $12 mathrmV·2.99 mathrmA + 48 mathrmV·0.82 mathrmA = 75.24 mathrmW$, in agreement with the 75 W power rating. This, combined with how simple this interpretation of the markings is, is sufficient evidence for me to say with confidence that you are correct.
simulate this circuit – Schematic created using CircuitLab
edited 3 hours ago
Jasen
11.4k1531
answered 4 hours ago
HearthHearth
4,6601137
$endgroup$
add a comment |
$begingroup$
Yes, your interpretation of the label is correct as far as I can tell.
Note also that $12 mathrmV·2.99 mathrmA + 48 mathrmV·0.82 mathrmA = 75.24 mathrmW$, in agreement with the 75 W power rating. This, combined with how simple this interpretation of the markings is, is sufficient evidence for me to say with confidence that you are correct.
simulate this circuit – Schematic created using CircuitLab
edited 3 hours ago
Jasen
11.4k1531
answered 4 hours ago
HearthHearth
4,6601137
$endgroup$
add a comment |
$begingroup$
Yes, your interpretation of the label is correct as far as I can tell.
Note also that $12 mathrmV·2.99 mathrmA + 48 mathrmV·0.82 mathrmA = 75.24 mathrmW$, in agreement with the 75 W power rating. This, combined with how simple this interpretation of the markings is, is sufficient evidence for me to say with confidence that you are correct.
simulate this circuit – Schematic created using CircuitLab
edited 3 hours ago
Jasen
11.4k1531
answered 4 hours ago
HearthHearth
4,6601137
$endgroup$
Yes, your interpretation of the label is correct as far as I can tell.
Note also that $12 mathrmV·2.99 mathrmA + 48 mathrmV·0.82 mathrmA = 75.24 mathrmW$, in agreement with the 75 W power rating. This, combined with how simple this interpretation of the markings is, is sufficient evidence for me to say with confidence that you are correct.
simulate this circuit – Schematic created using CircuitLab
edited 3 hours ago
Jasen
11.4k1531
answered 4 hours ago
HearthHearth
4,6601137
edited 3 hours ago
Jasen
11.4k1531
edited 3 hours ago
Jasen
11.4k1531
edited 3 hours ago
Jasen
11.4k1531
11.4k1531
answered 4 hours ago
HearthHearth
4,6601137
answered 4 hours ago
HearthHearth
4,6601137
answered 4 hours ago
HearthHearth
4,6601137
4,6601137
add a comment |
add a comment |
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93cNkaO,zi9sWBgk
2
$begingroup$
To me it seems your interpretation of the label is correct.
$endgroup$
– K. S.
5 hours ago
1
$begingroup$
@K.S. I thought so. It appears obvious, but I thought I'd ask the experts.
$endgroup$
– stevieb
5 hours ago