Passing args from the bash script to the function in the script Unicorn Meta Zoo #1: Why another podcast? Announcing the arrival of Valued Associate #679: Cesar Manara 2019 Community Moderator Election Results Why I closed the “Why is Kali so hard” questionAre there naming conventions for variables in shell scripts?When is double-quoting necessary?How can we run a command stored in a variable?Passing a stream to a bash functionPassing script string to ssh from within a bash script function - variable evaluation problembash script - loop functionShell script - command always display usage before executingrsync using function argsBash script inheritance? Calling a function from another script?Passing options/args/parameters with spaces from the script to a function withinPassing a boolean flag to a function?Dynamically read bash function name from inside bash functionrunning bash script from cron job not working properly
As an international instructor, should I openly talk about my accent?
How long after the last departure shall the airport stay open for an emergency return?
Could Neutrino technically as side-effect, incentivize centralization of the bitcoin network?
Why does the Cisco show run command not show the full version, while the show version command does?
Has a Nobel Peace laureate ever been accused of war crimes?
Is this homebrew racial feat, Stonehide, balanced?
Protagonist's race is hidden - should I reveal it?
Error: Syntax error. Missing ')' for CASE Statement
The art of proof summarizing. Are there known rules, or is it a purely common sense matter?
Map material from china not allowed to leave the country
Are these square matrices always diagonalisable?
How do I check if a string is entirely made of the same substring?
Implementing 3DES algorithm in Java: is my code secure?
Additive group of local rings
What is the ongoing value of the Kanban board to the developers as opposed to management
Multiple fireplaces in an apartment building?
Justification for leaving new position after a short time
What's the difference between using dependency injection with a container and using a service locator?
Is Electric Central Heating worth it if using Solar Panels?
Would reducing the reference voltage of an ADC have any effect on accuracy?
Are all CP/M-80 implementations binary compatible?
What is it called when you ride around on your front wheel?
Need of separate security plugins for both root and subfolder sites Wordpress?
Mistake in years of experience in resume?
Passing args from the bash script to the function in the script
Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar Manara
2019 Community Moderator Election Results
Why I closed the “Why is Kali so hard” questionAre there naming conventions for variables in shell scripts?When is double-quoting necessary?How can we run a command stored in a variable?Passing a stream to a bash functionPassing script string to ssh from within a bash script function - variable evaluation problembash script - loop functionShell script - command always display usage before executingrsync using function argsBash script inheritance? Calling a function from another script?Passing options/args/parameters with spaces from the script to a function withinPassing a boolean flag to a function?Dynamically read bash function name from inside bash functionrunning bash script from cron job not working properly
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
My script:
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local ENV="$1"
local VERB="$2"
local SERVICE="$3"
local CMD="docker-compose -f $ENV.yml"
case "$VERB" in
(exec)
shift "$#" # remove args passed to this fn
# Execute a command in a running container.
if [ -n "$SERVICE" ]; then
$CMD "$VERB" "$SERVICE" "$@"
else
echo "## Err: You must specify service name..."
exit 1
fi
;;
esac
compose_fn "$1" "$2" "$3"
Is giving me a hard time with the following error:
$ ./tst.sh dev exec django sh
+ compose_fn dev exec django
+ local ENV=dev
+ local VERB=exec
+ local SERVICE=django
+ local 'CMD=docker-compose -f dev.yml'
+ case "$VERB" in
+ shift 3
+ '[' -n django ']'
+ docker-compose -f dev.yml exec django
Execute a command in a running container
Usage: exec [options] [-e KEY=VAL...] SERVICE COMMAND [ARGS...]
Options:
....
Where is my mistake? How can it be done better?
As far as I can tell I've passed 4 args [dev, exec, django, sh]
to the script, then within the script removed 3 (shift 3
), therefore sh
should have been left in the $@
var.
bash shell-script shell
add a comment |
My script:
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local ENV="$1"
local VERB="$2"
local SERVICE="$3"
local CMD="docker-compose -f $ENV.yml"
case "$VERB" in
(exec)
shift "$#" # remove args passed to this fn
# Execute a command in a running container.
if [ -n "$SERVICE" ]; then
$CMD "$VERB" "$SERVICE" "$@"
else
echo "## Err: You must specify service name..."
exit 1
fi
;;
esac
compose_fn "$1" "$2" "$3"
Is giving me a hard time with the following error:
$ ./tst.sh dev exec django sh
+ compose_fn dev exec django
+ local ENV=dev
+ local VERB=exec
+ local SERVICE=django
+ local 'CMD=docker-compose -f dev.yml'
+ case "$VERB" in
+ shift 3
+ '[' -n django ']'
+ docker-compose -f dev.yml exec django
Execute a command in a running container
Usage: exec [options] [-e KEY=VAL...] SERVICE COMMAND [ARGS...]
Options:
....
Where is my mistake? How can it be done better?
As far as I can tell I've passed 4 args [dev, exec, django, sh]
to the script, then within the script removed 3 (shift 3
), therefore sh
should have been left in the $@
var.
bash shell-script shell
add a comment |
My script:
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local ENV="$1"
local VERB="$2"
local SERVICE="$3"
local CMD="docker-compose -f $ENV.yml"
case "$VERB" in
(exec)
shift "$#" # remove args passed to this fn
# Execute a command in a running container.
if [ -n "$SERVICE" ]; then
$CMD "$VERB" "$SERVICE" "$@"
else
echo "## Err: You must specify service name..."
exit 1
fi
;;
esac
compose_fn "$1" "$2" "$3"
Is giving me a hard time with the following error:
$ ./tst.sh dev exec django sh
+ compose_fn dev exec django
+ local ENV=dev
+ local VERB=exec
+ local SERVICE=django
+ local 'CMD=docker-compose -f dev.yml'
+ case "$VERB" in
+ shift 3
+ '[' -n django ']'
+ docker-compose -f dev.yml exec django
Execute a command in a running container
Usage: exec [options] [-e KEY=VAL...] SERVICE COMMAND [ARGS...]
Options:
....
Where is my mistake? How can it be done better?
As far as I can tell I've passed 4 args [dev, exec, django, sh]
to the script, then within the script removed 3 (shift 3
), therefore sh
should have been left in the $@
var.
bash shell-script shell
My script:
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local ENV="$1"
local VERB="$2"
local SERVICE="$3"
local CMD="docker-compose -f $ENV.yml"
case "$VERB" in
(exec)
shift "$#" # remove args passed to this fn
# Execute a command in a running container.
if [ -n "$SERVICE" ]; then
$CMD "$VERB" "$SERVICE" "$@"
else
echo "## Err: You must specify service name..."
exit 1
fi
;;
esac
compose_fn "$1" "$2" "$3"
Is giving me a hard time with the following error:
$ ./tst.sh dev exec django sh
+ compose_fn dev exec django
+ local ENV=dev
+ local VERB=exec
+ local SERVICE=django
+ local 'CMD=docker-compose -f dev.yml'
+ case "$VERB" in
+ shift 3
+ '[' -n django ']'
+ docker-compose -f dev.yml exec django
Execute a command in a running container
Usage: exec [options] [-e KEY=VAL...] SERVICE COMMAND [ARGS...]
Options:
....
Where is my mistake? How can it be done better?
As far as I can tell I've passed 4 args [dev, exec, django, sh]
to the script, then within the script removed 3 (shift 3
), therefore sh
should have been left in the $@
var.
bash shell-script shell
bash shell-script shell
edited 2 hours ago
NarūnasK
asked 2 hours ago
NarūnasKNarūnasK
9171722
9171722
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
With shift $#
you empty $@
completely. The $@
in the function is separate from the $@
in the main script. Why don't you just pass all arguments to the function and then shift off the first three?
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local env="$1"
local verb="$2"
local service="$3"
local cmd=( docker-compose -f "$env.yml" )
shift 3 # we've now used up three arguments
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
compose_fn "$@"
I've also used lower-case variable names so that no system or special shell variables are used by accident (ENV
is one that some shell uses under some circumstances, for example), and I've removed all unneeded quotes and curly braces.
I've also put the command into an array, so that we can quote the YAML filename properly.
You could also just move the setting of the three variables outside of the function, depending on what the rest of the script looks like and if this makes any sense at all. The three variables would then be global in the script.
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local cmd=( docker-compose -f "$env.yml" )
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
env="$1"
verb="$2"
service="$3"
shift 3
compose_fn "$@"
You may also bypass the [ -n "$service" ]
test with
service=$3:?'## Err: You must specify service name...'
The parameter expansion $parameter:?word
will exit the shell with the message defined by word
if parameter
is unset or empty. The bash
shell would format this as
script.sh: line 9: 3: ## Err: You must specify service name...
Related:
- When is double-quoting necessary?
- How can we run a command stored in a variable?
- Are there naming conventions for variables in shell scripts?
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f515342%2fpassing-args-from-the-bash-script-to-the-function-in-the-script%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
With shift $#
you empty $@
completely. The $@
in the function is separate from the $@
in the main script. Why don't you just pass all arguments to the function and then shift off the first three?
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local env="$1"
local verb="$2"
local service="$3"
local cmd=( docker-compose -f "$env.yml" )
shift 3 # we've now used up three arguments
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
compose_fn "$@"
I've also used lower-case variable names so that no system or special shell variables are used by accident (ENV
is one that some shell uses under some circumstances, for example), and I've removed all unneeded quotes and curly braces.
I've also put the command into an array, so that we can quote the YAML filename properly.
You could also just move the setting of the three variables outside of the function, depending on what the rest of the script looks like and if this makes any sense at all. The three variables would then be global in the script.
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local cmd=( docker-compose -f "$env.yml" )
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
env="$1"
verb="$2"
service="$3"
shift 3
compose_fn "$@"
You may also bypass the [ -n "$service" ]
test with
service=$3:?'## Err: You must specify service name...'
The parameter expansion $parameter:?word
will exit the shell with the message defined by word
if parameter
is unset or empty. The bash
shell would format this as
script.sh: line 9: 3: ## Err: You must specify service name...
Related:
- When is double-quoting necessary?
- How can we run a command stored in a variable?
- Are there naming conventions for variables in shell scripts?
add a comment |
With shift $#
you empty $@
completely. The $@
in the function is separate from the $@
in the main script. Why don't you just pass all arguments to the function and then shift off the first three?
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local env="$1"
local verb="$2"
local service="$3"
local cmd=( docker-compose -f "$env.yml" )
shift 3 # we've now used up three arguments
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
compose_fn "$@"
I've also used lower-case variable names so that no system or special shell variables are used by accident (ENV
is one that some shell uses under some circumstances, for example), and I've removed all unneeded quotes and curly braces.
I've also put the command into an array, so that we can quote the YAML filename properly.
You could also just move the setting of the three variables outside of the function, depending on what the rest of the script looks like and if this makes any sense at all. The three variables would then be global in the script.
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local cmd=( docker-compose -f "$env.yml" )
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
env="$1"
verb="$2"
service="$3"
shift 3
compose_fn "$@"
You may also bypass the [ -n "$service" ]
test with
service=$3:?'## Err: You must specify service name...'
The parameter expansion $parameter:?word
will exit the shell with the message defined by word
if parameter
is unset or empty. The bash
shell would format this as
script.sh: line 9: 3: ## Err: You must specify service name...
Related:
- When is double-quoting necessary?
- How can we run a command stored in a variable?
- Are there naming conventions for variables in shell scripts?
add a comment |
With shift $#
you empty $@
completely. The $@
in the function is separate from the $@
in the main script. Why don't you just pass all arguments to the function and then shift off the first three?
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local env="$1"
local verb="$2"
local service="$3"
local cmd=( docker-compose -f "$env.yml" )
shift 3 # we've now used up three arguments
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
compose_fn "$@"
I've also used lower-case variable names so that no system or special shell variables are used by accident (ENV
is one that some shell uses under some circumstances, for example), and I've removed all unneeded quotes and curly braces.
I've also put the command into an array, so that we can quote the YAML filename properly.
You could also just move the setting of the three variables outside of the function, depending on what the rest of the script looks like and if this makes any sense at all. The three variables would then be global in the script.
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local cmd=( docker-compose -f "$env.yml" )
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
env="$1"
verb="$2"
service="$3"
shift 3
compose_fn "$@"
You may also bypass the [ -n "$service" ]
test with
service=$3:?'## Err: You must specify service name...'
The parameter expansion $parameter:?word
will exit the shell with the message defined by word
if parameter
is unset or empty. The bash
shell would format this as
script.sh: line 9: 3: ## Err: You must specify service name...
Related:
- When is double-quoting necessary?
- How can we run a command stored in a variable?
- Are there naming conventions for variables in shell scripts?
With shift $#
you empty $@
completely. The $@
in the function is separate from the $@
in the main script. Why don't you just pass all arguments to the function and then shift off the first three?
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local env="$1"
local verb="$2"
local service="$3"
local cmd=( docker-compose -f "$env.yml" )
shift 3 # we've now used up three arguments
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
compose_fn "$@"
I've also used lower-case variable names so that no system or special shell variables are used by accident (ENV
is one that some shell uses under some circumstances, for example), and I've removed all unneeded quotes and curly braces.
I've also put the command into an array, so that we can quote the YAML filename properly.
You could also just move the setting of the three variables outside of the function, depending on what the rest of the script looks like and if this makes any sense at all. The three variables would then be global in the script.
#! /bin/bash --
set -x
## docker-compose wrapper
compose_fn()
local cmd=( docker-compose -f "$env.yml" )
case $verb in
exec)
# Execute a command in a running container.
if [ -n "$service" ]; then
"$cmd[@]" "$verb" "$service" "$@"
else
echo '## Err: You must specify service name...' >&2
exit 1
fi
;;
*)
printf 'Unknown verb: %sn' "$verb" >&2
exit 1
esac
env="$1"
verb="$2"
service="$3"
shift 3
compose_fn "$@"
You may also bypass the [ -n "$service" ]
test with
service=$3:?'## Err: You must specify service name...'
The parameter expansion $parameter:?word
will exit the shell with the message defined by word
if parameter
is unset or empty. The bash
shell would format this as
script.sh: line 9: 3: ## Err: You must specify service name...
Related:
- When is double-quoting necessary?
- How can we run a command stored in a variable?
- Are there naming conventions for variables in shell scripts?
edited 1 hour ago
answered 1 hour ago
Kusalananda♦Kusalananda
143k18267445
143k18267445
add a comment |
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f515342%2fpassing-args-from-the-bash-script-to-the-function-in-the-script%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown