“is” operation returns false even though two objects have same id The 2019 Stack Overflow Developer Survey Results Are In Unicorn Meta Zoo #1: Why another podcast? Announcing the arrival of Valued Associate #679: Cesar Manara The Ask Question Wizard is Live! Data science time! April 2019 and salary with experienceHow to return multiple values from a function?Does Python have a ternary conditional operator?Relationship between SciPy and NumPyCreating a singleton in PythonPython: two objects are the sameWhy is [] faster than list()?Why does “not(True) in [False, True]” return False?is comparison returns False with strings using same idHow can two Python objects have same id but 'is' operator returns False?Comparing Objects - Why is == returning 'False' in the following example?

Define a list range inside a list

How to read αἱμύλιος or when to aspirate

Huge performance difference of the command find with and without using %M option to show permissions

How to handle characters who are more educated than the author?

Single author papers against my advisor's will?

What is the padding with red substance inside of steak packaging?

How many cones with angle theta can I pack into the unit sphere?

Is an up-to-date browser secure on an out-of-date OS?

Did the UK government pay "millions and millions of dollars" to try to snag Julian Assange?

How do you keep chess fun when your opponent constantly beats you?

Presidential Pardon

My body leaves; my core can stay

"... to apply for a visa" or "... and applied for a visa"?

"is" operation returns false even though two objects have same id

Does Parliament hold absolute power in the UK?

Didn't get enough time to take a Coding Test - what to do now?

Variable with quotation marks "$()"

Can a flute soloist sit?

Can the Right Ascension and Argument of Perigee of a spacecraft's orbit keep varying by themselves with time?

Working through the single responsibility principle (SRP) in Python when calls are expensive

Deal with toxic manager when you can't quit

Solving overdetermined system by QR decomposition

Is every episode of "Where are my Pants?" identical?

Store Dynamic-accessible hidden metadata in a cell



“is” operation returns false even though two objects have same id



The 2019 Stack Overflow Developer Survey Results Are In
Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar Manara
The Ask Question Wizard is Live!
Data science time! April 2019 and salary with experienceHow to return multiple values from a function?Does Python have a ternary conditional operator?Relationship between SciPy and NumPyCreating a singleton in PythonPython: two objects are the sameWhy is [] faster than list()?Why does “not(True) in [False, True]” return False?is comparison returns False with strings using same idHow can two Python objects have same id but 'is' operator returns False?Comparing Objects - Why is == returning 'False' in the following example?



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








8















Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!










share|improve this question



















  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    4 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    4 hours ago






  • 1





    @Aran-Fey, that's okay a good question(though asked before) can sometimes be resurrected for a fruitful discussion

    – amanb
    4 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    3 hours ago






  • 2





    @juanpa.arrivillaga fair enough. Thanks for the explanation

    – C.Nivs
    2 hours ago

















8















Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!










share|improve this question



















  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    4 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    4 hours ago






  • 1





    @Aran-Fey, that's okay a good question(though asked before) can sometimes be resurrected for a fruitful discussion

    – amanb
    4 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    3 hours ago






  • 2





    @juanpa.arrivillaga fair enough. Thanks for the explanation

    – C.Nivs
    2 hours ago













8












8








8








Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!










share|improve this question
















Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!







python numpy






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 3 hours ago









ribitskiyb

376




376










asked 4 hours ago









drminixdrminix

513




513







  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    4 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    4 hours ago






  • 1





    @Aran-Fey, that's okay a good question(though asked before) can sometimes be resurrected for a fruitful discussion

    – amanb
    4 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    3 hours ago






  • 2





    @juanpa.arrivillaga fair enough. Thanks for the explanation

    – C.Nivs
    2 hours ago












  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    4 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    4 hours ago






  • 1





    @Aran-Fey, that's okay a good question(though asked before) can sometimes be resurrected for a fruitful discussion

    – amanb
    4 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    3 hours ago






  • 2





    @juanpa.arrivillaga fair enough. Thanks for the explanation

    – C.Nivs
    2 hours ago







1




1





@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

– chepner
4 hours ago





@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

– chepner
4 hours ago




2




2





@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

– chepner
4 hours ago





@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

– chepner
4 hours ago




1




1





@Aran-Fey, that's okay a good question(though asked before) can sometimes be resurrected for a fruitful discussion

– amanb
4 hours ago





@Aran-Fey, that's okay a good question(though asked before) can sometimes be resurrected for a fruitful discussion

– amanb
4 hours ago




1




1





@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

– juanpa.arrivillaga
3 hours ago





@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

– juanpa.arrivillaga
3 hours ago




2




2





@juanpa.arrivillaga fair enough. Thanks for the explanation

– C.Nivs
2 hours ago





@juanpa.arrivillaga fair enough. Thanks for the explanation

– C.Nivs
2 hours ago












2 Answers
2






active

oldest

votes


















12














a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



In the second if statement, each object is released as soon as id returns its id.



If you save references to both objects, keeping them alive, you can see they are not the same object.



r0 = a.data
r1 = c.data
assert r0 is not r1





share|improve this answer




















  • 4





    what is confusing is the fact that data looks like an attribute, but is probably a property

    – Jean-François Fabre
    4 hours ago











  • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

    – amanb
    4 hours ago











  • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

    – C.Nivs
    4 hours ago






  • 5





    a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

    – Jean-François Fabre
    4 hours ago


















3














In [62]: a = np.arange(12).reshape(2,-1) 
...: c = a.reshape(12,1)


.data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



In [63]: a.data 
Out[63]: <memory at 0x7f672d1101f8>
In [64]: c.data
Out[64]: <memory at 0x7f672d1103a8>
In [65]: type(a.data)
Out[65]: memoryview


https://docs.python.org/3/library/stdtypes.html#memoryview



If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



In [66]: a.__array_interface__['data'] 
Out[66]: (50988640, False)
In [67]: c.__array_interface__['data']
Out[67]: (50988640, False)


It even shows the offset produced by slicing - here 24 bytes, 3*8



In [68]: c[3:].__array_interface__['data'] 
Out[68]: (50988664, False)



I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
In [71]: d
Out[71]:
array([[ 0, 1, 2, 3, 4, 5],
[ 6, 7, 8, 9, 10, 11]])
In [72]: d.__array_interface__['data']
Out[72]: (50988640, False)


But normally we create new arrays with shared memory with slicing or np.array (copy=False).






share|improve this answer

























    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55658189%2fis-operation-returns-false-even-though-two-objects-have-same-id%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    12














    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1





    share|improve this answer




















    • 4





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      4 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      4 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      4 hours ago






    • 5





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      4 hours ago















    12














    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1





    share|improve this answer




















    • 4





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      4 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      4 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      4 hours ago






    • 5





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      4 hours ago













    12












    12








    12







    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1





    share|improve this answer















    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 4 hours ago

























    answered 4 hours ago









    chepnerchepner

    262k35251345




    262k35251345







    • 4





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      4 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      4 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      4 hours ago






    • 5





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      4 hours ago












    • 4





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      4 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      4 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      4 hours ago






    • 5





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      4 hours ago







    4




    4





    what is confusing is the fact that data looks like an attribute, but is probably a property

    – Jean-François Fabre
    4 hours ago





    what is confusing is the fact that data looks like an attribute, but is probably a property

    – Jean-François Fabre
    4 hours ago













    In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

    – amanb
    4 hours ago





    In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

    – amanb
    4 hours ago













    @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

    – C.Nivs
    4 hours ago





    @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

    – C.Nivs
    4 hours ago




    5




    5





    a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

    – Jean-François Fabre
    4 hours ago





    a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

    – Jean-François Fabre
    4 hours ago













    3














    In [62]: a = np.arange(12).reshape(2,-1) 
    ...: c = a.reshape(12,1)


    .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



    In [63]: a.data 
    Out[63]: <memory at 0x7f672d1101f8>
    In [64]: c.data
    Out[64]: <memory at 0x7f672d1103a8>
    In [65]: type(a.data)
    Out[65]: memoryview


    https://docs.python.org/3/library/stdtypes.html#memoryview



    If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



    In [66]: a.__array_interface__['data'] 
    Out[66]: (50988640, False)
    In [67]: c.__array_interface__['data']
    Out[67]: (50988640, False)


    It even shows the offset produced by slicing - here 24 bytes, 3*8



    In [68]: c[3:].__array_interface__['data'] 
    Out[68]: (50988664, False)



    I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



    In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
    In [71]: d
    Out[71]:
    array([[ 0, 1, 2, 3, 4, 5],
    [ 6, 7, 8, 9, 10, 11]])
    In [72]: d.__array_interface__['data']
    Out[72]: (50988640, False)


    But normally we create new arrays with shared memory with slicing or np.array (copy=False).






    share|improve this answer





























      3














      In [62]: a = np.arange(12).reshape(2,-1) 
      ...: c = a.reshape(12,1)


      .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



      In [63]: a.data 
      Out[63]: <memory at 0x7f672d1101f8>
      In [64]: c.data
      Out[64]: <memory at 0x7f672d1103a8>
      In [65]: type(a.data)
      Out[65]: memoryview


      https://docs.python.org/3/library/stdtypes.html#memoryview



      If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



      In [66]: a.__array_interface__['data'] 
      Out[66]: (50988640, False)
      In [67]: c.__array_interface__['data']
      Out[67]: (50988640, False)


      It even shows the offset produced by slicing - here 24 bytes, 3*8



      In [68]: c[3:].__array_interface__['data'] 
      Out[68]: (50988664, False)



      I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



      In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
      In [71]: d
      Out[71]:
      array([[ 0, 1, 2, 3, 4, 5],
      [ 6, 7, 8, 9, 10, 11]])
      In [72]: d.__array_interface__['data']
      Out[72]: (50988640, False)


      But normally we create new arrays with shared memory with slicing or np.array (copy=False).






      share|improve this answer



























        3












        3








        3







        In [62]: a = np.arange(12).reshape(2,-1) 
        ...: c = a.reshape(12,1)


        .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



        In [63]: a.data 
        Out[63]: <memory at 0x7f672d1101f8>
        In [64]: c.data
        Out[64]: <memory at 0x7f672d1103a8>
        In [65]: type(a.data)
        Out[65]: memoryview


        https://docs.python.org/3/library/stdtypes.html#memoryview



        If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



        In [66]: a.__array_interface__['data'] 
        Out[66]: (50988640, False)
        In [67]: c.__array_interface__['data']
        Out[67]: (50988640, False)


        It even shows the offset produced by slicing - here 24 bytes, 3*8



        In [68]: c[3:].__array_interface__['data'] 
        Out[68]: (50988664, False)



        I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



        In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
        In [71]: d
        Out[71]:
        array([[ 0, 1, 2, 3, 4, 5],
        [ 6, 7, 8, 9, 10, 11]])
        In [72]: d.__array_interface__['data']
        Out[72]: (50988640, False)


        But normally we create new arrays with shared memory with slicing or np.array (copy=False).






        share|improve this answer















        In [62]: a = np.arange(12).reshape(2,-1) 
        ...: c = a.reshape(12,1)


        .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



        In [63]: a.data 
        Out[63]: <memory at 0x7f672d1101f8>
        In [64]: c.data
        Out[64]: <memory at 0x7f672d1103a8>
        In [65]: type(a.data)
        Out[65]: memoryview


        https://docs.python.org/3/library/stdtypes.html#memoryview



        If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



        In [66]: a.__array_interface__['data'] 
        Out[66]: (50988640, False)
        In [67]: c.__array_interface__['data']
        Out[67]: (50988640, False)


        It even shows the offset produced by slicing - here 24 bytes, 3*8



        In [68]: c[3:].__array_interface__['data'] 
        Out[68]: (50988664, False)



        I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



        In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
        In [71]: d
        Out[71]:
        array([[ 0, 1, 2, 3, 4, 5],
        [ 6, 7, 8, 9, 10, 11]])
        In [72]: d.__array_interface__['data']
        Out[72]: (50988640, False)


        But normally we create new arrays with shared memory with slicing or np.array (copy=False).







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 3 hours ago

























        answered 3 hours ago









        hpauljhpaulj

        118k787160




        118k787160



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55658189%2fis-operation-returns-false-even-though-two-objects-have-same-id%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Oświęcim Innehåll Historia | Källor | Externa länkar | Navigeringsmeny50°2′18″N 19°13′17″Ö / 50.03833°N 19.22139°Ö / 50.03833; 19.2213950°2′18″N 19°13′17″Ö / 50.03833°N 19.22139°Ö / 50.03833; 19.221393089658Nordisk familjebok, AuschwitzInsidan tro och existensJewish Community i OświęcimAuschwitz Jewish Center: MuseumAuschwitz Jewish Center

            Valle di Casies Indice Geografia fisica | Origini del nome | Storia | Società | Amministrazione | Sport | Note | Bibliografia | Voci correlate | Altri progetti | Collegamenti esterni | Menu di navigazione46°46′N 12°11′E / 46.766667°N 12.183333°E46.766667; 12.183333 (Valle di Casies)46°46′N 12°11′E / 46.766667°N 12.183333°E46.766667; 12.183333 (Valle di Casies)Sito istituzionaleAstat Censimento della popolazione 2011 - Determinazione della consistenza dei tre gruppi linguistici della Provincia Autonoma di Bolzano-Alto Adige - giugno 2012Numeri e fattiValle di CasiesDato IstatTabella dei gradi/giorno dei Comuni italiani raggruppati per Regione e Provincia26 agosto 1993, n. 412Heraldry of the World: GsiesStatistiche I.StatValCasies.comWikimedia CommonsWikimedia CommonsValle di CasiesSito ufficialeValle di CasiesMM14870458910042978-6

            Typsetting diagram chases (with TikZ?) Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)How to define the default vertical distance between nodes?Draw edge on arcNumerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to place nodes in an absolute coordinate system in tikzCommutative diagram with curve connecting between nodesTikz with standalone: pinning tikz coordinates to page cmDrawing a Decision Diagram with Tikz and layout manager