Copycat chess is backCopycat Chess (Part 3/3)Copycat Chess (Part 2/3)Copycat Chess (Part 1/3)The Erasmus rook tourCan you stop the rambling rook?No More Kings puzzleGetting rid of all chess pieces (except the kings) in a sequence consisting only of capturesA Chess Puzzle in ReverseA Battle of Dysfunctional Kings (Chess)The Fastest Queen Trap (Chess)Loser Chess : another proof gameThe Chess 24 GameHow many total checkmates can you possibly make against the enemy king?
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Copycat chess is back
Copycat Chess (Part 3/3)Copycat Chess (Part 2/3)Copycat Chess (Part 1/3)The Erasmus rook tourCan you stop the rambling rook?No More Kings puzzleGetting rid of all chess pieces (except the kings) in a sequence consisting only of capturesA Chess Puzzle in ReverseA Battle of Dysfunctional Kings (Chess)The Fastest Queen Trap (Chess)Loser Chess : another proof gameThe Chess 24 GameHow many total checkmates can you possibly make against the enemy king?
$begingroup$
This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
$endgroup$
add a comment |
$begingroup$
This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
$endgroup$
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
1 hour ago
add a comment |
$begingroup$
This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
$endgroup$
This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
chess
edited 1 hour ago
Arnaud Mortier
asked 1 hour ago
Arnaud MortierArnaud Mortier
2,117725
2,117725
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
1 hour ago
add a comment |
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
1 hour ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
$endgroup$
$begingroup$
Yep :) not the shortest though.
$endgroup$
– Arnaud Mortier
1 hour ago
3
$begingroup$
@Arnaud Mortier How about now
$endgroup$
– Penguino
1 hour ago
add a comment |
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
$endgroup$
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
59 mins ago
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
57 mins ago
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
51 mins ago
add a comment |
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
$endgroup$
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
1 hour ago
2
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
1 hour ago
add a comment |
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
$endgroup$
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
58 mins ago
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
57 mins ago
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
57 mins ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
$endgroup$
$begingroup$
Yep :) not the shortest though.
$endgroup$
– Arnaud Mortier
1 hour ago
3
$begingroup$
@Arnaud Mortier How about now
$endgroup$
– Penguino
1 hour ago
add a comment |
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
$endgroup$
$begingroup$
Yep :) not the shortest though.
$endgroup$
– Arnaud Mortier
1 hour ago
3
$begingroup$
@Arnaud Mortier How about now
$endgroup$
– Penguino
1 hour ago
add a comment |
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
$endgroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
edited 1 hour ago
answered 1 hour ago
PenguinoPenguino
7,1872168
7,1872168
$begingroup$
Yep :) not the shortest though.
$endgroup$
– Arnaud Mortier
1 hour ago
3
$begingroup$
@Arnaud Mortier How about now
$endgroup$
– Penguino
1 hour ago
add a comment |
$begingroup$
Yep :) not the shortest though.
$endgroup$
– Arnaud Mortier
1 hour ago
3
$begingroup$
@Arnaud Mortier How about now
$endgroup$
– Penguino
1 hour ago
$begingroup$
Yep :) not the shortest though.
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Yep :) not the shortest though.
$endgroup$
– Arnaud Mortier
1 hour ago
3
3
$begingroup$
@Arnaud Mortier How about now
$endgroup$
– Penguino
1 hour ago
$begingroup$
@Arnaud Mortier How about now
$endgroup$
– Penguino
1 hour ago
add a comment |
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
$endgroup$
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
59 mins ago
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
57 mins ago
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
51 mins ago
add a comment |
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
$endgroup$
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
59 mins ago
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
57 mins ago
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
51 mins ago
add a comment |
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
$endgroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
edited 45 mins ago
answered 59 mins ago
PiIsNot3PiIsNot3
1,742124
1,742124
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
59 mins ago
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
57 mins ago
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
51 mins ago
add a comment |
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
59 mins ago
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
57 mins ago
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
51 mins ago
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
59 mins ago
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
59 mins ago
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
57 mins ago
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
57 mins ago
1
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
51 mins ago
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
51 mins ago
add a comment |
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
$endgroup$
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
1 hour ago
2
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
1 hour ago
add a comment |
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
$endgroup$
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
1 hour ago
2
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
1 hour ago
add a comment |
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
$endgroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
answered 1 hour ago
El-GuestEl-Guest
21.5k25092
21.5k25092
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
1 hour ago
2
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
1 hour ago
add a comment |
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
1 hour ago
2
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
1 hour ago
1
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
1 hour ago
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
1 hour ago
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
1 hour ago
2
2
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
1 hour ago
add a comment |
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
$endgroup$
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
58 mins ago
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
57 mins ago
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
57 mins ago
add a comment |
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
$endgroup$
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
58 mins ago
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
57 mins ago
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
57 mins ago
add a comment |
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
$endgroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
edited 59 mins ago
answered 1 hour ago
Brandon_JBrandon_J
3,548244
3,548244
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
58 mins ago
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
57 mins ago
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
57 mins ago
add a comment |
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
58 mins ago
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
57 mins ago
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
57 mins ago
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
1 hour ago
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
1 hour ago
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
58 mins ago
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
58 mins ago
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
57 mins ago
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
57 mins ago
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
57 mins ago
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
57 mins ago
add a comment |
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$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
1 hour ago
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
1 hour ago