How to make `trap` know if the EXIT is after successful program finish or because of premature as an error or something The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Community Moderator Election ResultsError handling in shell scriptHow to trigger error using Trap commandPrevent SIGINT from interrupting function call and child process(es) withinHow to keep last exit status after testKeep exit codes when trapping SIGINT and similar?How to make `local` capture the exit code?Restoring tty correctly with sttyPerl: Error code returned to open3 after killed programexceptions to ERR trapShell_exec of dynamically created script with else
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How to make `trap` know if the EXIT is after successful program finish or because of premature as an error or something
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How to make `trap` know if the EXIT is after successful program finish or because of premature as an error or something
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Community Moderator Election ResultsError handling in shell scriptHow to trigger error using Trap commandPrevent SIGINT from interrupting function call and child process(es) withinHow to keep last exit status after testKeep exit codes when trapping SIGINT and similar?How to make `local` capture the exit code?Restoring tty correctly with sttyPerl: Error code returned to open3 after killed programexceptions to ERR trapShell_exec of dynamically created script with else
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PROBLEM:
I have a shell program that I have been writing but I can't find out how to make sure that trap
is trapping for cleanup at the end or because of a error in some command, it cleans up either way.
Here is the code:
################################### Successful exit then this cleanup ###########################################################3
successfulExit()
###############################################################################################################################33
####### Catch the program on successful exit and cleanup
trap successfulExit EXIT
QUESTION:
How can I make trap
only trap EXIT
on program finish?
Here is the full script:
debianConfigAwsome.5.3.sh
shell-script exit-status trap
add a comment |
PROBLEM:
I have a shell program that I have been writing but I can't find out how to make sure that trap
is trapping for cleanup at the end or because of a error in some command, it cleans up either way.
Here is the code:
################################### Successful exit then this cleanup ###########################################################3
successfulExit()
###############################################################################################################################33
####### Catch the program on successful exit and cleanup
trap successfulExit EXIT
QUESTION:
How can I make trap
only trap EXIT
on program finish?
Here is the full script:
debianConfigAwsome.5.3.sh
shell-script exit-status trap
add a comment |
PROBLEM:
I have a shell program that I have been writing but I can't find out how to make sure that trap
is trapping for cleanup at the end or because of a error in some command, it cleans up either way.
Here is the code:
################################### Successful exit then this cleanup ###########################################################3
successfulExit()
###############################################################################################################################33
####### Catch the program on successful exit and cleanup
trap successfulExit EXIT
QUESTION:
How can I make trap
only trap EXIT
on program finish?
Here is the full script:
debianConfigAwsome.5.3.sh
shell-script exit-status trap
PROBLEM:
I have a shell program that I have been writing but I can't find out how to make sure that trap
is trapping for cleanup at the end or because of a error in some command, it cleans up either way.
Here is the code:
################################### Successful exit then this cleanup ###########################################################3
successfulExit()
###############################################################################################################################33
####### Catch the program on successful exit and cleanup
trap successfulExit EXIT
QUESTION:
How can I make trap
only trap EXIT
on program finish?
Here is the full script:
debianConfigAwsome.5.3.sh
shell-script exit-status trap
shell-script exit-status trap
edited 2 hours ago
muru
37.6k589165
37.6k589165
asked 7 hours ago
somethingSomethingsomethingSomething
1,850103460
1,850103460
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
On entry to the EXIT
trap, $?
contains the exit status. That's the same value you'd find as $?
after calling this script in another shell: either the argument passed to exit
(truncated to the range 0–255) or the return status of the preceding command. In the case of an exit due to set -e
, it's the return status of the command that triggered the implicit exit
.
Usually you should save $?
and exit again with the same status.
cleanup ()
if [ -n "$1" ]; then
echo "Aborted by $1"
elif [ $status -ne 0 ]; then
echo "Failure (status $status)"
else
echo "Success"
fi
trap 'status=$?; cleanup; exit $status' EXIT
trap 'trap - HUP; cleanup SIGHUP; kill -HUP $$' HUP
trap 'trap - INT; cleanup SIGINT; kill -INT $$' INT
trap 'trap - TERM; cleanup SIGTERM; kill -TERM $$' TERM
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
On entry to the EXIT
trap, $?
contains the exit status. That's the same value you'd find as $?
after calling this script in another shell: either the argument passed to exit
(truncated to the range 0–255) or the return status of the preceding command. In the case of an exit due to set -e
, it's the return status of the command that triggered the implicit exit
.
Usually you should save $?
and exit again with the same status.
cleanup ()
if [ -n "$1" ]; then
echo "Aborted by $1"
elif [ $status -ne 0 ]; then
echo "Failure (status $status)"
else
echo "Success"
fi
trap 'status=$?; cleanup; exit $status' EXIT
trap 'trap - HUP; cleanup SIGHUP; kill -HUP $$' HUP
trap 'trap - INT; cleanup SIGINT; kill -INT $$' INT
trap 'trap - TERM; cleanup SIGTERM; kill -TERM $$' TERM
add a comment |
On entry to the EXIT
trap, $?
contains the exit status. That's the same value you'd find as $?
after calling this script in another shell: either the argument passed to exit
(truncated to the range 0–255) or the return status of the preceding command. In the case of an exit due to set -e
, it's the return status of the command that triggered the implicit exit
.
Usually you should save $?
and exit again with the same status.
cleanup ()
if [ -n "$1" ]; then
echo "Aborted by $1"
elif [ $status -ne 0 ]; then
echo "Failure (status $status)"
else
echo "Success"
fi
trap 'status=$?; cleanup; exit $status' EXIT
trap 'trap - HUP; cleanup SIGHUP; kill -HUP $$' HUP
trap 'trap - INT; cleanup SIGINT; kill -INT $$' INT
trap 'trap - TERM; cleanup SIGTERM; kill -TERM $$' TERM
add a comment |
On entry to the EXIT
trap, $?
contains the exit status. That's the same value you'd find as $?
after calling this script in another shell: either the argument passed to exit
(truncated to the range 0–255) or the return status of the preceding command. In the case of an exit due to set -e
, it's the return status of the command that triggered the implicit exit
.
Usually you should save $?
and exit again with the same status.
cleanup ()
if [ -n "$1" ]; then
echo "Aborted by $1"
elif [ $status -ne 0 ]; then
echo "Failure (status $status)"
else
echo "Success"
fi
trap 'status=$?; cleanup; exit $status' EXIT
trap 'trap - HUP; cleanup SIGHUP; kill -HUP $$' HUP
trap 'trap - INT; cleanup SIGINT; kill -INT $$' INT
trap 'trap - TERM; cleanup SIGTERM; kill -TERM $$' TERM
On entry to the EXIT
trap, $?
contains the exit status. That's the same value you'd find as $?
after calling this script in another shell: either the argument passed to exit
(truncated to the range 0–255) or the return status of the preceding command. In the case of an exit due to set -e
, it's the return status of the command that triggered the implicit exit
.
Usually you should save $?
and exit again with the same status.
cleanup ()
if [ -n "$1" ]; then
echo "Aborted by $1"
elif [ $status -ne 0 ]; then
echo "Failure (status $status)"
else
echo "Success"
fi
trap 'status=$?; cleanup; exit $status' EXIT
trap 'trap - HUP; cleanup SIGHUP; kill -HUP $$' HUP
trap 'trap - INT; cleanup SIGINT; kill -INT $$' INT
trap 'trap - TERM; cleanup SIGTERM; kill -TERM $$' TERM
answered 6 hours ago
GillesGilles
547k13011131631
547k13011131631
add a comment |
add a comment |
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