Scheduling based problem Unicorn Meta Zoo #1: Why another podcast? Announcing the arrival of Valued Associate #679: Cesar ManaraDeducing Two Numbers based on their Difference and RatioThe 2 million, er, 20 dollar problemAdd a number to each vertex of a triangle such that each edge adds to a perfect squareHexagonal sum fillingEight distinct numbers in the tableIncreasing rows and columnsA simple grid puzzle123456789=1 problemFilling a chessboard with -1, 0 and 1Input/Output Problem #7

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Scheduling based problem



Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar ManaraDeducing Two Numbers based on their Difference and RatioThe 2 million, er, 20 dollar problemAdd a number to each vertex of a triangle such that each edge adds to a perfect squareHexagonal sum fillingEight distinct numbers in the tableIncreasing rows and columnsA simple grid puzzle123456789=1 problemFilling a chessboard with -1, 0 and 1Input/Output Problem #7










2












$begingroup$


Can you place these numbers into 5 rows of 4 such that each row totals 20?




1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8











share|improve this question









$endgroup$
















    2












    $begingroup$


    Can you place these numbers into 5 rows of 4 such that each row totals 20?




    1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8











    share|improve this question









    $endgroup$














      2












      2








      2





      $begingroup$


      Can you place these numbers into 5 rows of 4 such that each row totals 20?




      1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8











      share|improve this question









      $endgroup$




      Can you place these numbers into 5 rows of 4 such that each row totals 20?




      1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8








      mathematics packing






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 1 hour ago









      JonMark PerryJonMark Perry

      20.9k64199




      20.9k64199




















          2 Answers
          2






          active

          oldest

          votes


















          3












          $begingroup$

          Sure.




          1,5,6,8

          2,4,6,8

          3,4,5,8

          4,4,5,7

          5,5,5,5




          Method:




          Started from the bigger numbers, and partitioned into 5 parts of 20: 8,8,4, 8,7,5 and so on.


          Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.




          With some fiddling, it's also possible to get all the columns to add up to 25:




          1,8,6,5

          5,4,7,4

          5,5,5,5

          6,4,2,8

          8,4,5,3




          And here's a magic square (with duplicates, unavoidably) followed by a row of fives:




          1,6,8,5

          5,7,4,4

          8,5,4,3

          6,2,4,8

          5,5,5,5







          share|improve this answer











          $endgroup$












          • $begingroup$
            I'm late ! But I have differents rows :D
            $endgroup$
            – Narlore
            1 hour ago










          • $begingroup$
            I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
            $endgroup$
            – 5202456
            14 mins ago


















          1












          $begingroup$

          This one works




          7 3 5 5

          8 2 5 5

          6 4 5 5

          8 6 1 5

          8 4 4 4




          Method :




          Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.







          share|improve this answer











          $endgroup$













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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3












            $begingroup$

            Sure.




            1,5,6,8

            2,4,6,8

            3,4,5,8

            4,4,5,7

            5,5,5,5




            Method:




            Started from the bigger numbers, and partitioned into 5 parts of 20: 8,8,4, 8,7,5 and so on.


            Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.




            With some fiddling, it's also possible to get all the columns to add up to 25:




            1,8,6,5

            5,4,7,4

            5,5,5,5

            6,4,2,8

            8,4,5,3




            And here's a magic square (with duplicates, unavoidably) followed by a row of fives:




            1,6,8,5

            5,7,4,4

            8,5,4,3

            6,2,4,8

            5,5,5,5







            share|improve this answer











            $endgroup$












            • $begingroup$
              I'm late ! But I have differents rows :D
              $endgroup$
              – Narlore
              1 hour ago










            • $begingroup$
              I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
              $endgroup$
              – 5202456
              14 mins ago















            3












            $begingroup$

            Sure.




            1,5,6,8

            2,4,6,8

            3,4,5,8

            4,4,5,7

            5,5,5,5




            Method:




            Started from the bigger numbers, and partitioned into 5 parts of 20: 8,8,4, 8,7,5 and so on.


            Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.




            With some fiddling, it's also possible to get all the columns to add up to 25:




            1,8,6,5

            5,4,7,4

            5,5,5,5

            6,4,2,8

            8,4,5,3




            And here's a magic square (with duplicates, unavoidably) followed by a row of fives:




            1,6,8,5

            5,7,4,4

            8,5,4,3

            6,2,4,8

            5,5,5,5







            share|improve this answer











            $endgroup$












            • $begingroup$
              I'm late ! But I have differents rows :D
              $endgroup$
              – Narlore
              1 hour ago










            • $begingroup$
              I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
              $endgroup$
              – 5202456
              14 mins ago













            3












            3








            3





            $begingroup$

            Sure.




            1,5,6,8

            2,4,6,8

            3,4,5,8

            4,4,5,7

            5,5,5,5




            Method:




            Started from the bigger numbers, and partitioned into 5 parts of 20: 8,8,4, 8,7,5 and so on.


            Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.




            With some fiddling, it's also possible to get all the columns to add up to 25:




            1,8,6,5

            5,4,7,4

            5,5,5,5

            6,4,2,8

            8,4,5,3




            And here's a magic square (with duplicates, unavoidably) followed by a row of fives:




            1,6,8,5

            5,7,4,4

            8,5,4,3

            6,2,4,8

            5,5,5,5







            share|improve this answer











            $endgroup$



            Sure.




            1,5,6,8

            2,4,6,8

            3,4,5,8

            4,4,5,7

            5,5,5,5




            Method:




            Started from the bigger numbers, and partitioned into 5 parts of 20: 8,8,4, 8,7,5 and so on.


            Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.




            With some fiddling, it's also possible to get all the columns to add up to 25:




            1,8,6,5

            5,4,7,4

            5,5,5,5

            6,4,2,8

            8,4,5,3




            And here's a magic square (with duplicates, unavoidably) followed by a row of fives:




            1,6,8,5

            5,7,4,4

            8,5,4,3

            6,2,4,8

            5,5,5,5








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 59 mins ago

























            answered 1 hour ago









            BassBass

            31.5k474192




            31.5k474192











            • $begingroup$
              I'm late ! But I have differents rows :D
              $endgroup$
              – Narlore
              1 hour ago










            • $begingroup$
              I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
              $endgroup$
              – 5202456
              14 mins ago
















            • $begingroup$
              I'm late ! But I have differents rows :D
              $endgroup$
              – Narlore
              1 hour ago










            • $begingroup$
              I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
              $endgroup$
              – 5202456
              14 mins ago















            $begingroup$
            I'm late ! But I have differents rows :D
            $endgroup$
            – Narlore
            1 hour ago




            $begingroup$
            I'm late ! But I have differents rows :D
            $endgroup$
            – Narlore
            1 hour ago












            $begingroup$
            I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
            $endgroup$
            – 5202456
            14 mins ago




            $begingroup$
            I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
            $endgroup$
            – 5202456
            14 mins ago











            1












            $begingroup$

            This one works




            7 3 5 5

            8 2 5 5

            6 4 5 5

            8 6 1 5

            8 4 4 4




            Method :




            Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.







            share|improve this answer











            $endgroup$

















              1












              $begingroup$

              This one works




              7 3 5 5

              8 2 5 5

              6 4 5 5

              8 6 1 5

              8 4 4 4




              Method :




              Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.







              share|improve this answer











              $endgroup$















                1












                1








                1





                $begingroup$

                This one works




                7 3 5 5

                8 2 5 5

                6 4 5 5

                8 6 1 5

                8 4 4 4




                Method :




                Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.







                share|improve this answer











                $endgroup$



                This one works




                7 3 5 5

                8 2 5 5

                6 4 5 5

                8 6 1 5

                8 4 4 4




                Method :




                Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.








                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 1 hour ago

























                answered 1 hour ago









                NarloreNarlore

                34615




                34615



























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