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How do I slice a string by characters in Python? [duplicate]

8

2

This question already has an answer here:

• 
  Python - Find sequence of same characters
  
  3 answers
  
  


• 
  Splitting a string with repeated characters into a list using regex
  
  3 answers
  
  

There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:

'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']

How do I make this in Python?

python

share|improve this question

edited 9 hours ago

Peter Mortensen

13.8k1986113

asked 14 hours ago

Hank ChowHank Chow

521

marked as duplicate by Kasrâmvd python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

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6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
  
  – Aran-Fey
  14 hours ago
  

  
  
  
  

add a comment | 

8

2

This question already has an answer here:

• 
  Python - Find sequence of same characters
  
  3 answers
  
  


• 
  Splitting a string with repeated characters into a list using regex
  
  3 answers
  
  

There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:

'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']

How do I make this in Python?

python

share|improve this question

edited 9 hours ago

Peter Mortensen

13.8k1986113

asked 14 hours ago

Hank ChowHank Chow

521

marked as duplicate by Kasrâmvd python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function()
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6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
  
  – Aran-Fey
  14 hours ago
  

  
  
  
  

add a comment | 

This question already has an answer here:

• 
  Python - Find sequence of same characters
  
  3 answers
  
  


• 
  Splitting a string with repeated characters into a list using regex
  
  3 answers
  
  

There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:

'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']

How do I make this in Python?

python

share|improve this question

edited 9 hours ago

Peter Mortensen

13.8k1986113

asked 14 hours ago

Hank ChowHank Chow

521

'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']

share|improve this question

edited 9 hours ago

Peter Mortensen

13.8k1986113

asked 14 hours ago

Hank ChowHank Chow

521

share|improve this question

edited 9 hours ago

Peter Mortensen

13.8k1986113

asked 14 hours ago

Hank ChowHank Chow

521

edited 9 hours ago

Peter Mortensen

13.8k1986113

edited 9 hours ago

Peter Mortensen

13.8k1986113

asked 14 hours ago

Hank ChowHank Chow

521

asked 14 hours ago

Hank ChowHank Chow

521

5 Answers
5

active

oldest

votes

15

Use itertools.groupby:

from itertools import groupby

s = 'abccbba'

print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']

share|improve this answer

edited 14 hours ago

Aran-Fey

20.9k53671

answered 14 hours ago

AustinAustin

12.3k3930

add a comment | 

4

Can be achieved with re.finditer()

import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']

share|improve this answer

answered 14 hours ago

denis_lordenis_lor

1,37111130

add a comment | 

2

Without any modules and using for loop also it can be done in interesting way:

l=[]
str="aabccc"
s=str[0]
for c in str[1:]:

 if(c!=s[-1]):
 l.append(s)
 s=c
 else:
 s=s+c
l.append(s)
print(l)

share|improve this answer

answered 13 hours ago

TojrahTojrah

461

New contributor

Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

2

Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.

from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, [])

share|improve this answer

answered 12 hours ago

quantummindquantummind

1,3541817

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  Wow...this is as unreadable as it could get...
  
  – heemayl
  11 hours ago
  

  
  
  
  

add a comment | 

1

t=input()
c=[t[0]]
for i in range(1,len(t)):
 if t[i]==c[-1][0]:
 c[-1]=c[-1]+t[i]
 else:
 c.append(t[i])
print(c)

share|improve this answer

answered 7 hours ago

Mr.AMr.A

112

New contributor

Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please add some text to make the answer more descriptive.
  
  – v.coder
  6 hours ago
  

  
  
  
  

add a comment | 

15

Use itertools.groupby:

from itertools import groupby

s = 'abccbba'

print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']

share|improve this answer

edited 14 hours ago

Aran-Fey

20.9k53671

answered 14 hours ago

AustinAustin

12.3k3930

add a comment | 

15

Use itertools.groupby:

from itertools import groupby

s = 'abccbba'

print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']

share|improve this answer

edited 14 hours ago

Aran-Fey

20.9k53671

answered 14 hours ago

AustinAustin

12.3k3930

add a comment | 

Use itertools.groupby:

from itertools import groupby

s = 'abccbba'

print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']

share|improve this answer

edited 14 hours ago

Aran-Fey

20.9k53671

answered 14 hours ago

AustinAustin

12.3k3930

from itertools import groupby

s = 'abccbba'

print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']

share|improve this answer

edited 14 hours ago

Aran-Fey

20.9k53671

answered 14 hours ago

AustinAustin

12.3k3930

edited 14 hours ago

Aran-Fey

20.9k53671

edited 14 hours ago

Aran-Fey

20.9k53671

answered 14 hours ago

AustinAustin

12.3k3930

answered 14 hours ago

AustinAustin

12.3k3930

4

Can be achieved with re.finditer()

import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']

share|improve this answer

answered 14 hours ago

denis_lordenis_lor

1,37111130

add a comment | 

4

Can be achieved with re.finditer()

import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']

share|improve this answer

answered 14 hours ago

denis_lordenis_lor

1,37111130

add a comment | 

Can be achieved with re.finditer()

import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']

share|improve this answer

answered 14 hours ago

denis_lordenis_lor

1,37111130

import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']

share|improve this answer

answered 14 hours ago

denis_lordenis_lor

1,37111130

answered 14 hours ago

denis_lordenis_lor

1,37111130

answered 14 hours ago

denis_lordenis_lor

1,37111130

2

Without any modules and using for loop also it can be done in interesting way:

l=[]
str="aabccc"
s=str[0]
for c in str[1:]:

 if(c!=s[-1]):
 l.append(s)
 s=c
 else:
 s=s+c
l.append(s)
print(l)

share|improve this answer

answered 13 hours ago

TojrahTojrah

461

New contributor

Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

2

Without any modules and using for loop also it can be done in interesting way:

l=[]
str="aabccc"
s=str[0]
for c in str[1:]:

 if(c!=s[-1]):
 l.append(s)
 s=c
 else:
 s=s+c
l.append(s)
print(l)

share|improve this answer

answered 13 hours ago

TojrahTojrah

461

New contributor

Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

Without any modules and using for loop also it can be done in interesting way:

l=[]
str="aabccc"
s=str[0]
for c in str[1:]:

 if(c!=s[-1]):
 l.append(s)
 s=c
 else:
 s=s+c
l.append(s)
print(l)

share|improve this answer

answered 13 hours ago

TojrahTojrah

461

New contributor

Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

l=[]
str="aabccc"
s=str[0]
for c in str[1:]:

 if(c!=s[-1]):
 l.append(s)
 s=c
 else:
 s=s+c
l.append(s)
print(l)

share|improve this answer

answered 13 hours ago

TojrahTojrah

461

New contributor

Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 13 hours ago

TojrahTojrah

461

New contributor

Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 13 hours ago

TojrahTojrah

461

2

Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.

from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, [])

share|improve this answer

answered 12 hours ago

quantummindquantummind

1,3541817

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  Wow...this is as unreadable as it could get...
  
  – heemayl
  11 hours ago
  

  
  
  
  

add a comment | 

2

Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.

from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, [])

share|improve this answer

answered 12 hours ago

quantummindquantummind

1,3541817

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  Wow...this is as unreadable as it could get...
  
  – heemayl
  11 hours ago
  

  
  
  
  

add a comment | 

Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.

from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, [])

share|improve this answer

answered 12 hours ago

quantummindquantummind

1,3541817

from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, [])

share|improve this answer

answered 12 hours ago

quantummindquantummind

1,3541817

answered 12 hours ago

quantummindquantummind

1,3541817

answered 12 hours ago

quantummindquantummind

1,3541817

1

t=input()
c=[t[0]]
for i in range(1,len(t)):
 if t[i]==c[-1][0]:
 c[-1]=c[-1]+t[i]
 else:
 c.append(t[i])
print(c)

share|improve this answer

answered 7 hours ago

Mr.AMr.A

112

New contributor

Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please add some text to make the answer more descriptive.
  
  – v.coder
  6 hours ago
  

  
  
  
  

add a comment | 

1

t=input()
c=[t[0]]
for i in range(1,len(t)):
 if t[i]==c[-1][0]:
 c[-1]=c[-1]+t[i]
 else:
 c.append(t[i])
print(c)

share|improve this answer

answered 7 hours ago

Mr.AMr.A

112

New contributor

Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please add some text to make the answer more descriptive.
  
  – v.coder
  6 hours ago
  

  
  
  
  

add a comment | 

t=input()
c=[t[0]]
for i in range(1,len(t)):
 if t[i]==c[-1][0]:
 c[-1]=c[-1]+t[i]
 else:
 c.append(t[i])
print(c)

share|improve this answer

answered 7 hours ago

Mr.AMr.A

112

New contributor

Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

t=input()
c=[t[0]]
for i in range(1,len(t)):
 if t[i]==c[-1][0]:
 c[-1]=c[-1]+t[i]
 else:
 c.append(t[i])
print(c)

share|improve this answer

answered 7 hours ago

Mr.AMr.A

112

New contributor

Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 7 hours ago

Mr.AMr.A

112

New contributor

Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 7 hours ago

Mr.AMr.A

112