Double integral with logarithms Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)An interesting integral expression for $pi^n$?Integral involving Laguerre, Gaussian and modified Bessel functionhow to solve the rational exp integral?Nested trigonometric integralI want to disprove an equality involving a double integralIntegral of product of Gaussian pdf and cdfRewriting an elliptic integral in terms of theta functionsHow to solve this integral equation?Leibniz rule for Hadamard derivative?Integral of Classical Entropy

Double integral with logarithms



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)An interesting integral expression for $pi^n$?Integral involving Laguerre, Gaussian and modified Bessel functionhow to solve the rational exp integral?Nested trigonometric integralI want to disprove an equality involving a double integralIntegral of product of Gaussian pdf and cdfRewriting an elliptic integral in terms of theta functionsHow to solve this integral equation?Leibniz rule for Hadamard derivative?Integral of Classical Entropy










3












$begingroup$


How to solve this integral:



$$Jequiv int_0^1int_0^1fracln x-ln yx-ydxdy$$



I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$fracpi ^23.$$



Thanks!.










share|cite|improve this question









New contributor




Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 4




    $begingroup$
    MSE is a right place for such type questions. Both Maple and Mathematica confirm $ fracpi ^23$.
    $endgroup$
    – user64494
    2 hours ago






  • 4




    $begingroup$
    I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
    $endgroup$
    – RP_
    2 hours ago










  • $begingroup$
    @user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
    $endgroup$
    – Fedor Petrov
    4 mins ago















3












$begingroup$


How to solve this integral:



$$Jequiv int_0^1int_0^1fracln x-ln yx-ydxdy$$



I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$fracpi ^23.$$



Thanks!.










share|cite|improve this question









New contributor




Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 4




    $begingroup$
    MSE is a right place for such type questions. Both Maple and Mathematica confirm $ fracpi ^23$.
    $endgroup$
    – user64494
    2 hours ago






  • 4




    $begingroup$
    I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
    $endgroup$
    – RP_
    2 hours ago










  • $begingroup$
    @user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
    $endgroup$
    – Fedor Petrov
    4 mins ago













3












3








3


1



$begingroup$


How to solve this integral:



$$Jequiv int_0^1int_0^1fracln x-ln yx-ydxdy$$



I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$fracpi ^23.$$



Thanks!.










share|cite|improve this question









New contributor




Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




How to solve this integral:



$$Jequiv int_0^1int_0^1fracln x-ln yx-ydxdy$$



I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$fracpi ^23.$$



Thanks!.







integral






share|cite|improve this question









New contributor




Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 2 hours ago









user64494

1,818617




1,818617






New contributor




Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 3 hours ago









Jesús Álvarez LoboJesús Álvarez Lobo

221




221




New contributor




Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Jesús Álvarez Lobo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 4




    $begingroup$
    MSE is a right place for such type questions. Both Maple and Mathematica confirm $ fracpi ^23$.
    $endgroup$
    – user64494
    2 hours ago






  • 4




    $begingroup$
    I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
    $endgroup$
    – RP_
    2 hours ago










  • $begingroup$
    @user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
    $endgroup$
    – Fedor Petrov
    4 mins ago












  • 4




    $begingroup$
    MSE is a right place for such type questions. Both Maple and Mathematica confirm $ fracpi ^23$.
    $endgroup$
    – user64494
    2 hours ago






  • 4




    $begingroup$
    I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
    $endgroup$
    – RP_
    2 hours ago










  • $begingroup$
    @user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
    $endgroup$
    – Fedor Petrov
    4 mins ago







4




4




$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ fracpi ^23$.
$endgroup$
– user64494
2 hours ago




$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ fracpi ^23$.
$endgroup$
– user64494
2 hours ago




4




4




$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
2 hours ago




$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
2 hours ago












$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
4 mins ago




$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
4 mins ago










1 Answer
1






active

oldest

votes


















7












$begingroup$

By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 fraclog t 1-tdt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac11 - t =sum_n>0 t^n-1$ and integrate term-wise to get $sum 1/n^2$).






share|cite|improve this answer











$endgroup$













    Your Answer








    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "504"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );






    Jesús Álvarez Lobo is a new contributor. Be nice, and check out our Code of Conduct.









    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f328124%2fdouble-integral-with-logarithms%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7












    $begingroup$

    By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 fraclog t 1-tdt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac11 - t =sum_n>0 t^n-1$ and integrate term-wise to get $sum 1/n^2$).






    share|cite|improve this answer











    $endgroup$

















      7












      $begingroup$

      By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 fraclog t 1-tdt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac11 - t =sum_n>0 t^n-1$ and integrate term-wise to get $sum 1/n^2$).






      share|cite|improve this answer











      $endgroup$















        7












        7








        7





        $begingroup$

        By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 fraclog t 1-tdt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac11 - t =sum_n>0 t^n-1$ and integrate term-wise to get $sum 1/n^2$).






        share|cite|improve this answer











        $endgroup$



        By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 fraclog t 1-tdt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac11 - t =sum_n>0 t^n-1$ and integrate term-wise to get $sum 1/n^2$).







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 1 hour ago









        T. Amdeberhan

        18.4k230132




        18.4k230132










        answered 3 hours ago









        Fedor PetrovFedor Petrov

        52.3k6122239




        52.3k6122239




















            Jesús Álvarez Lobo is a new contributor. Be nice, and check out our Code of Conduct.









            draft saved

            draft discarded


















            Jesús Álvarez Lobo is a new contributor. Be nice, and check out our Code of Conduct.












            Jesús Álvarez Lobo is a new contributor. Be nice, and check out our Code of Conduct.











            Jesús Álvarez Lobo is a new contributor. Be nice, and check out our Code of Conduct.














            Thanks for contributing an answer to MathOverflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f328124%2fdouble-integral-with-logarithms%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Bett Inhaltsverzeichnis Geschichte | Bettformen | Bettgrößen | Andere Bezeichnungen | Bettenmangel | Betten in der bildenden Kunst | Schlafmedizinische Gesichtspunkte | Siehe auch | Literatur | Weblinks | Einzelnachweise | NavigationsmenüBett, Bettstatt, BettstelleCommons: BettBabybetten: Anwendung, Ausstattungsmerkmale und VergleichskriterienWasserbetten. Vorurteile im TestHapfnNursch10.1007/s11818-012-0584-74006250-8AKS4329276-8

            Luksemburg Sisukord Nimi | Asend | Loodus | Riigikord | Haldusjaotus | Rahvastik | Riigikaitse | Majandus | Taristu | Ajalugu | Eesti ja Luksemburgi suhted | Haridus | Kultuur | Vaata ka | Viited | Välislingid | Navigeerimismenüü50° N, 6° EÜlevaade Luksemburgi kaitsealadest.Luksemburgi rahvaarv. Statistikaamet.World Bank'i andmebaasÜlevaade Luksemburgi loodusest.Ülevaade Luksemburgi metsadest.Guy Colling. "Red List of the Vascular Plants of Luxembourg." Travaux scientifiques du Musée national d’histoire naturelle Luxembourg. 2005.Luxembourg’s biodiversity at risk.Maailma kahepaiksete andmebaas.Denis Lepage. "Luxembourg." Avibase.Ülevaade temperatuuridest. Luksemburgi meteoroloogiateenistus.Ülevaade Luksemburgist. Euroopa Liidu esinduse koduleht.Système politique. TerritoireÜlevaade Luksemburgi rahvastikust. Luksemburgi statistikaamet.Luksemburgi rahvastik. Luksemburgi statistikaamet.The World FactbookMonique Borsenberger, Paul Dickes. "Religions au Luxembourg. Quelle évolution entre 1999-2008". Luksemburgi statistikaamet. 2011.Luksemburgi peapiiskopkond. Catholic-Hierarchy.Luksemburgi armee koduleht.Luksemburgi armee relvastus.Eesti Välisministeerium.Luksemburgi rahvastik. Luksemburgi statistikaamet.Luksemburgi Eesti Seltsi koduleht.Helen Eelrand. "Raadio, mis muutis maailma." Eesti Päevaleht. 13. märts 2004.Ülevaade Luksemburgi haridussüsteemist.Ülevaade Luksemburgi keskkoolidest.Luksemburgr

            Valle di Casies Indice Geografia fisica | Origini del nome | Storia | Società | Amministrazione | Sport | Note | Bibliografia | Voci correlate | Altri progetti | Collegamenti esterni | Menu di navigazione46°46′N 12°11′E / 46.766667°N 12.183333°E46.766667; 12.183333 (Valle di Casies)46°46′N 12°11′E / 46.766667°N 12.183333°E46.766667; 12.183333 (Valle di Casies)Sito istituzionaleAstat Censimento della popolazione 2011 - Determinazione della consistenza dei tre gruppi linguistici della Provincia Autonoma di Bolzano-Alto Adige - giugno 2012Numeri e fattiValle di CasiesDato IstatTabella dei gradi/giorno dei Comuni italiani raggruppati per Regione e Provincia26 agosto 1993, n. 412Heraldry of the World: GsiesStatistiche I.StatValCasies.comWikimedia CommonsWikimedia CommonsValle di CasiesSito ufficialeValle di CasiesMM14870458910042978-6