Regex in IF condition in awk Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Community Moderator Election Results Why I closed the “Why is Kali so hard” questionHow to use regrex with AWK for string replacement in this example?Regex for matchng anything between parenthesisawk adds extra comma at several placesawk ifs and variables - cannot pass a variable from one line towards subsequent linesUsing multiple awk commands within single lineBest way to iterate through the following awk commandawk or sed command to match regex at specific line, exit true if success, false otherwiseHow to add a condition within a for loop during substitution if string is nullPrint text before and after match, from a specific beginning and to an ending stringsearch column 2 in csv file for value, if value, then insert “invalid” and shift cells right
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Regex in IF condition in awk
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Regex in IF condition in awk
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Community Moderator Election Results
Why I closed the “Why is Kali so hard” questionHow to use regrex with AWK for string replacement in this example?Regex for matchng anything between parenthesisawk adds extra comma at several placesawk ifs and variables - cannot pass a variable from one line towards subsequent linesUsing multiple awk commands within single lineBest way to iterate through the following awk commandawk or sed command to match regex at specific line, exit true if success, false otherwiseHow to add a condition within a for loop during substitution if string is nullPrint text before and after match, from a specific beginning and to an ending stringsearch column 2 in csv file for value, if value, then insert “invalid” and shift cells right
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I have awk script file as below. I need to add another condition in the if statement to check if the string contains atleast one alphabet. How can I add the extra condition to the present if statement?
Required regex condition: [[ "$1" =~ [A-Za-z] ]]
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12))
counter++
print counter, $1;
if ($counter -gt 2)
print "Invalid input file";
exit;
I am getting error if I use the same condition which I have posted. How to add the condition?
awk regular-expression
edited 3 hours ago
muru
37.9k590166
asked 4 hours ago
LaxmanLaxman
254
add a comment |
I have awk script file as below. I need to add another condition in the if statement to check if the string contains atleast one alphabet. How can I add the extra condition to the present if statement?
Required regex condition: [[ "$1" =~ [A-Za-z] ]]
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12))
counter++
print counter, $1;
if ($counter -gt 2)
print "Invalid input file";
exit;
I am getting error if I use the same condition which I have posted. How to add the condition?
awk regular-expression
edited 3 hours ago
muru
37.9k590166
asked 4 hours ago
LaxmanLaxman
254
1
See the examples here: gnu.org/software/gawk/manual/gawk.html#Regexp-Usage
– steeldriver
4 hours ago
How do you add it? You are showing us a bash-style if statement. The regex is fine, but the regex is just[A-Za-z]. What are you adding to yourawk?
– terdon♦
4 hours ago
add a comment |
I have awk script file as below. I need to add another condition in the if statement to check if the string contains atleast one alphabet. How can I add the extra condition to the present if statement?
Required regex condition: [[ "$1" =~ [A-Za-z] ]]
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12))
counter++
print counter, $1;
if ($counter -gt 2)
print "Invalid input file";
exit;
I am getting error if I use the same condition which I have posted. How to add the condition?
awk regular-expression
edited 3 hours ago
muru
37.9k590166
asked 4 hours ago
LaxmanLaxman
254
I have awk script file as below. I need to add another condition in the if statement to check if the string contains atleast one alphabet. How can I add the extra condition to the present if statement?
Required regex condition: [[ "$1" =~ [A-Za-z] ]]
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12))
counter++
print counter, $1;
if ($counter -gt 2)
print "Invalid input file";
exit;
I am getting error if I use the same condition which I have posted. How to add the condition?
awk regular-expression
awk regular-expression
edited 3 hours ago
muru
37.9k590166
asked 4 hours ago
LaxmanLaxman
254
edited 3 hours ago
muru
37.9k590166
asked 4 hours ago
LaxmanLaxman
254
edited 3 hours ago
muru
37.9k590166
edited 3 hours ago
muru
37.9k590166
edited 3 hours ago
muru
37.9k590166
37.9k590166
asked 4 hours ago
LaxmanLaxman
254
asked 4 hours ago
LaxmanLaxman
254
asked 4 hours ago
LaxmanLaxman
254
254
1
See the examples here: gnu.org/software/gawk/manual/gawk.html#Regexp-Usage
– steeldriver
4 hours ago
How do you add it? You are showing us a bash-style if statement. The regex is fine, but the regex is just[A-Za-z]. What are you adding to yourawk?
– terdon♦
4 hours ago
add a comment |
1
See the examples here: gnu.org/software/gawk/manual/gawk.html#Regexp-Usage
– steeldriver
4 hours ago
How do you add it? You are showing us a bash-style if statement. The regex is fine, but the regex is just[A-Za-z]. What are you adding to yourawk?
– terdon♦
4 hours ago
1
1
See the examples here: gnu.org/software/gawk/manual/gawk.html#Regexp-Usage
– steeldriver
4 hours ago
See the examples here: gnu.org/software/gawk/manual/gawk.html#Regexp-Usage
– steeldriver
4 hours ago
How do you add it? You are showing us a bash-style if statement. The regex is fine, but the regex is just
[A-Za-z]. What are you adding to your awk?– terdon♦
4 hours ago
How do you add it? You are showing us a bash-style if statement. The regex is fine, but the regex is just
[A-Za-z]. What are you adding to your awk?– terdon♦
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
You don't actually show how you add the regex, so I am guessing you are using the same format: =~ [A-Za-z]. That won't work. Each language has its own syntax for regex matching. In awk, the format is $target ~ /$regex/, so $1 ~ /[A-Za-z]/.
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12) && $1 ~ /[A-Za-z]/)
counter++
print counter, $1;
if (counter > 2)
print "Invalid input file";
exit;
Also, in awk, the $ sign is used to mark fields, not variables. So $counter will be evaluated to the field number of counter. If counter is 2, then $counter will be the value of the second field. And the -gt is also not an awk thing. Just use >.
answered 4 hours ago
terdon♦terdon
134k33270450
Yes. I was using=~format.
– Laxman
4 hours ago
add a comment |
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votes
You don't actually show how you add the regex, so I am guessing you are using the same format: =~ [A-Za-z]. That won't work. Each language has its own syntax for regex matching. In awk, the format is $target ~ /$regex/, so $1 ~ /[A-Za-z]/.
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12) && $1 ~ /[A-Za-z]/)
counter++
print counter, $1;
if (counter > 2)
print "Invalid input file";
exit;
Also, in awk, the $ sign is used to mark fields, not variables. So $counter will be evaluated to the field number of counter. If counter is 2, then $counter will be the value of the second field. And the -gt is also not an awk thing. Just use >.
answered 4 hours ago
terdon♦terdon
134k33270450
Yes. I was using=~format.
– Laxman
4 hours ago
add a comment |
You don't actually show how you add the regex, so I am guessing you are using the same format: =~ [A-Za-z]. That won't work. Each language has its own syntax for regex matching. In awk, the format is $target ~ /$regex/, so $1 ~ /[A-Za-z]/.
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12) && $1 ~ /[A-Za-z]/)
counter++
print counter, $1;
if (counter > 2)
print "Invalid input file";
exit;
Also, in awk, the $ sign is used to mark fields, not variables. So $counter will be evaluated to the field number of counter. If counter is 2, then $counter will be the value of the second field. And the -gt is also not an awk thing. Just use >.
answered 4 hours ago
terdon♦terdon
134k33270450
Yes. I was using=~format.
– Laxman
4 hours ago
add a comment |
You don't actually show how you add the regex, so I am guessing you are using the same format: =~ [A-Za-z]. That won't work. Each language has its own syntax for regex matching. In awk, the format is $target ~ /$regex/, so $1 ~ /[A-Za-z]/.
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12) && $1 ~ /[A-Za-z]/)
counter++
print counter, $1;
if (counter > 2)
print "Invalid input file";
exit;
Also, in awk, the $ sign is used to mark fields, not variables. So $counter will be evaluated to the field number of counter. If counter is 2, then $counter will be the value of the second field. And the -gt is also not an awk thing. Just use >.
answered 4 hours ago
terdon♦terdon
134k33270450
You don't actually show how you add the regex, so I am guessing you are using the same format: =~ [A-Za-z]. That won't work. Each language has its own syntax for regex matching. In awk, the format is $target ~ /$regex/, so $1 ~ /[A-Za-z]/.
BEGIN FS = ";"; counter=0
if ((length($1) != 10 && length($1) != 12) && $1 ~ /[A-Za-z]/)
counter++
print counter, $1;
if (counter > 2)
print "Invalid input file";
exit;
Also, in awk, the $ sign is used to mark fields, not variables. So $counter will be evaluated to the field number of counter. If counter is 2, then $counter will be the value of the second field. And the -gt is also not an awk thing. Just use >.
answered 4 hours ago
terdon♦terdon
134k33270450
answered 4 hours ago
terdon♦terdon
134k33270450
answered 4 hours ago
terdon♦terdon
134k33270450
answered 4 hours ago
terdon♦terdon
134k33270450
134k33270450
Yes. I was using=~format.
– Laxman
4 hours ago
add a comment |
Yes. I was using=~format.
– Laxman
4 hours ago
Yes. I was using
=~ format.– Laxman
4 hours ago
Yes. I was using
=~ format.– Laxman
4 hours ago
add a comment |
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See the examples here: gnu.org/software/gawk/manual/gawk.html#Regexp-Usage
– steeldriver
4 hours ago
How do you add it? You are showing us a bash-style if statement. The regex is fine, but the regex is just
[A-Za-z]. What are you adding to yourawk?– terdon♦
4 hours ago