ListPlot join points by nearest neighbor rather than order Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Interpolation on large 2D list results in erratic functionHow can I combine several 2D-plots to one big 3D plot?ListContourPlot3D blank box?Does anyone know a way to draw lines connecting nearest neighbor points in ListPlot[ ]?PlotRange->Automatic the exact function used to calculate outliersI need help on plotting surface through my list of data pointsHow do I make ListPlot join the points in order?ListContourPlot not plotting all data pointsMathematica returns a blank coordinate system when I try to plot dataMore resolution on ListContourPlot?
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ListPlot join points by nearest neighbor rather than order
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Interpolation on large 2D list results in erratic functionHow can I combine several 2D-plots to one big 3D plot?ListContourPlot3D blank box?Does anyone know a way to draw lines connecting nearest neighbor points in ListPlot[ ]?PlotRange->Automatic the exact function used to calculate outliersI need help on plotting surface through my list of data pointsHow do I make ListPlot join the points in order?ListContourPlot not plotting all data pointsMathematica returns a blank coordinate system when I try to plot dataMore resolution on ListContourPlot?
$begingroup$
I have found some software that allows me to "data mine" the values from publication figures. I have a bunch of contours from papers that I've mined using this software, and am having some trouble plotting the points with the Joined command.
Unfortunately, the downloaded points are sorted by increasing x values, which makes the plotting of Gaussian-esque contours very difficult. I've searched around the forums and haven't found anyone mentioning this problem.
Here's an example on a very small, simpler distribution (note my other sets are much larger so brute force definitely won't work.)
data=62.0774, 0.598737, 62.2377, 0.619119, 62.4048,
0.580509, 62.5466, 0.637818, 62.9276, 0.654518, 62.9668,
0.566973, 63.3095, 0.671261, 63.8137, 0.688518, 63.8913,
0.565805, 64.4067, 0.703821, 64.8157, 0.568541, 65.1005,
0.718671, 65.7401, 0.573603, 65.9282, 0.732056, 66.6646,
0.580678, 66.7973, 0.743456, 67.6058, 0.589303, 67.7571,
0.755602, 68.5512, 0.599853, 68.6815, 0.761419, 69.4,
0.614478, 69.6059, 0.76384, 70.1679, 0.631668, 70.5117,
0.759937, 70.5514, 0.759266, 70.7216, 0.649606, 71.3609,
0.666955, 71.3764, 0.751005, 71.7909, 0.736308, 71.8078,
0.687055, 71.947, 0.702022, 72.0491, 0.717738
ListPlot[data]

gives me this:
While
ListLinePlot[data]
of course gives me this, because the points are ordered with increasing x-value:
So, is there any way to either join the points by nearest neighbor, or re-order the list such that the joined command will give me a neat line? This seems like a traveling-salesman type problem, which could quickly get slow as I increase the number of points too much.
plotting order
$endgroup$
add a comment |
$begingroup$
I have found some software that allows me to "data mine" the values from publication figures. I have a bunch of contours from papers that I've mined using this software, and am having some trouble plotting the points with the Joined command.
Unfortunately, the downloaded points are sorted by increasing x values, which makes the plotting of Gaussian-esque contours very difficult. I've searched around the forums and haven't found anyone mentioning this problem.
Here's an example on a very small, simpler distribution (note my other sets are much larger so brute force definitely won't work.)
data=62.0774, 0.598737, 62.2377, 0.619119, 62.4048,
0.580509, 62.5466, 0.637818, 62.9276, 0.654518, 62.9668,
0.566973, 63.3095, 0.671261, 63.8137, 0.688518, 63.8913,
0.565805, 64.4067, 0.703821, 64.8157, 0.568541, 65.1005,
0.718671, 65.7401, 0.573603, 65.9282, 0.732056, 66.6646,
0.580678, 66.7973, 0.743456, 67.6058, 0.589303, 67.7571,
0.755602, 68.5512, 0.599853, 68.6815, 0.761419, 69.4,
0.614478, 69.6059, 0.76384, 70.1679, 0.631668, 70.5117,
0.759937, 70.5514, 0.759266, 70.7216, 0.649606, 71.3609,
0.666955, 71.3764, 0.751005, 71.7909, 0.736308, 71.8078,
0.687055, 71.947, 0.702022, 72.0491, 0.717738
ListPlot[data]

gives me this:
While
ListLinePlot[data]
of course gives me this, because the points are ordered with increasing x-value:
So, is there any way to either join the points by nearest neighbor, or re-order the list such that the joined command will give me a neat line? This seems like a traveling-salesman type problem, which could quickly get slow as I increase the number of points too much.
plotting order
$endgroup$
1
$begingroup$
TryFindShortestTour
$endgroup$
– C. E.
3 hours ago
1
$begingroup$
Try something likeListLinePlot[data[[Last@FindShortestTour@data]]]but it is not perfect
$endgroup$
– J42161217
2 hours ago
add a comment |
$begingroup$
I have found some software that allows me to "data mine" the values from publication figures. I have a bunch of contours from papers that I've mined using this software, and am having some trouble plotting the points with the Joined command.
Unfortunately, the downloaded points are sorted by increasing x values, which makes the plotting of Gaussian-esque contours very difficult. I've searched around the forums and haven't found anyone mentioning this problem.
Here's an example on a very small, simpler distribution (note my other sets are much larger so brute force definitely won't work.)
data=62.0774, 0.598737, 62.2377, 0.619119, 62.4048,
0.580509, 62.5466, 0.637818, 62.9276, 0.654518, 62.9668,
0.566973, 63.3095, 0.671261, 63.8137, 0.688518, 63.8913,
0.565805, 64.4067, 0.703821, 64.8157, 0.568541, 65.1005,
0.718671, 65.7401, 0.573603, 65.9282, 0.732056, 66.6646,
0.580678, 66.7973, 0.743456, 67.6058, 0.589303, 67.7571,
0.755602, 68.5512, 0.599853, 68.6815, 0.761419, 69.4,
0.614478, 69.6059, 0.76384, 70.1679, 0.631668, 70.5117,
0.759937, 70.5514, 0.759266, 70.7216, 0.649606, 71.3609,
0.666955, 71.3764, 0.751005, 71.7909, 0.736308, 71.8078,
0.687055, 71.947, 0.702022, 72.0491, 0.717738
ListPlot[data]

gives me this:
While
ListLinePlot[data]
of course gives me this, because the points are ordered with increasing x-value:
So, is there any way to either join the points by nearest neighbor, or re-order the list such that the joined command will give me a neat line? This seems like a traveling-salesman type problem, which could quickly get slow as I increase the number of points too much.
plotting order
$endgroup$
I have found some software that allows me to "data mine" the values from publication figures. I have a bunch of contours from papers that I've mined using this software, and am having some trouble plotting the points with the Joined command.
Unfortunately, the downloaded points are sorted by increasing x values, which makes the plotting of Gaussian-esque contours very difficult. I've searched around the forums and haven't found anyone mentioning this problem.
Here's an example on a very small, simpler distribution (note my other sets are much larger so brute force definitely won't work.)
data=62.0774, 0.598737, 62.2377, 0.619119, 62.4048,
0.580509, 62.5466, 0.637818, 62.9276, 0.654518, 62.9668,
0.566973, 63.3095, 0.671261, 63.8137, 0.688518, 63.8913,
0.565805, 64.4067, 0.703821, 64.8157, 0.568541, 65.1005,
0.718671, 65.7401, 0.573603, 65.9282, 0.732056, 66.6646,
0.580678, 66.7973, 0.743456, 67.6058, 0.589303, 67.7571,
0.755602, 68.5512, 0.599853, 68.6815, 0.761419, 69.4,
0.614478, 69.6059, 0.76384, 70.1679, 0.631668, 70.5117,
0.759937, 70.5514, 0.759266, 70.7216, 0.649606, 71.3609,
0.666955, 71.3764, 0.751005, 71.7909, 0.736308, 71.8078,
0.687055, 71.947, 0.702022, 72.0491, 0.717738
ListPlot[data]

gives me this:
While
ListLinePlot[data]
of course gives me this, because the points are ordered with increasing x-value:
So, is there any way to either join the points by nearest neighbor, or re-order the list such that the joined command will give me a neat line? This seems like a traveling-salesman type problem, which could quickly get slow as I increase the number of points too much.
plotting order
plotting order
asked 3 hours ago
zackzack
716
716
1
$begingroup$
TryFindShortestTour
$endgroup$
– C. E.
3 hours ago
1
$begingroup$
Try something likeListLinePlot[data[[Last@FindShortestTour@data]]]but it is not perfect
$endgroup$
– J42161217
2 hours ago
add a comment |
1
$begingroup$
TryFindShortestTour
$endgroup$
– C. E.
3 hours ago
1
$begingroup$
Try something likeListLinePlot[data[[Last@FindShortestTour@data]]]but it is not perfect
$endgroup$
– J42161217
2 hours ago
1
1
$begingroup$
Try
FindShortestTour$endgroup$
– C. E.
3 hours ago
$begingroup$
Try
FindShortestTour$endgroup$
– C. E.
3 hours ago
1
1
$begingroup$
Try something like
ListLinePlot[data[[Last@FindShortestTour@data]]] but it is not perfect$endgroup$
– J42161217
2 hours ago
$begingroup$
Try something like
ListLinePlot[data[[Last@FindShortestTour@data]]] but it is not perfect$endgroup$
– J42161217
2 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can use FindCurvePath to reorder your data. However, FindCurvePath expects the scale of the two coordinates to be close, so you need to rescale first:
new = FindCurvePath[data . 1, 0, 0, 100];
ListLinePlot[data[[#]]& /@ new]

$endgroup$
$begingroup$
Why not just the closely relatedListCurvePathPlot?
$endgroup$
– Roman
1 hour ago
$begingroup$
@Roman Did you try usingListCurvePathPlot? Because the data has such a small variation in theycoordinate,ListCurvePathPlotdoesn't work well. That's why I scaled the data and usedFindCurvePathto reorder the data, and then plotted the reordered data.
$endgroup$
– Carl Woll
46 mins ago
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use FindCurvePath to reorder your data. However, FindCurvePath expects the scale of the two coordinates to be close, so you need to rescale first:
new = FindCurvePath[data . 1, 0, 0, 100];
ListLinePlot[data[[#]]& /@ new]

$endgroup$
$begingroup$
Why not just the closely relatedListCurvePathPlot?
$endgroup$
– Roman
1 hour ago
$begingroup$
@Roman Did you try usingListCurvePathPlot? Because the data has such a small variation in theycoordinate,ListCurvePathPlotdoesn't work well. That's why I scaled the data and usedFindCurvePathto reorder the data, and then plotted the reordered data.
$endgroup$
– Carl Woll
46 mins ago
add a comment |
$begingroup$
You can use FindCurvePath to reorder your data. However, FindCurvePath expects the scale of the two coordinates to be close, so you need to rescale first:
new = FindCurvePath[data . 1, 0, 0, 100];
ListLinePlot[data[[#]]& /@ new]

$endgroup$
$begingroup$
Why not just the closely relatedListCurvePathPlot?
$endgroup$
– Roman
1 hour ago
$begingroup$
@Roman Did you try usingListCurvePathPlot? Because the data has such a small variation in theycoordinate,ListCurvePathPlotdoesn't work well. That's why I scaled the data and usedFindCurvePathto reorder the data, and then plotted the reordered data.
$endgroup$
– Carl Woll
46 mins ago
add a comment |
$begingroup$
You can use FindCurvePath to reorder your data. However, FindCurvePath expects the scale of the two coordinates to be close, so you need to rescale first:
new = FindCurvePath[data . 1, 0, 0, 100];
ListLinePlot[data[[#]]& /@ new]

$endgroup$
You can use FindCurvePath to reorder your data. However, FindCurvePath expects the scale of the two coordinates to be close, so you need to rescale first:
new = FindCurvePath[data . 1, 0, 0, 100];
ListLinePlot[data[[#]]& /@ new]

answered 1 hour ago
Carl WollCarl Woll
74.1k398193
74.1k398193
$begingroup$
Why not just the closely relatedListCurvePathPlot?
$endgroup$
– Roman
1 hour ago
$begingroup$
@Roman Did you try usingListCurvePathPlot? Because the data has such a small variation in theycoordinate,ListCurvePathPlotdoesn't work well. That's why I scaled the data and usedFindCurvePathto reorder the data, and then plotted the reordered data.
$endgroup$
– Carl Woll
46 mins ago
add a comment |
$begingroup$
Why not just the closely relatedListCurvePathPlot?
$endgroup$
– Roman
1 hour ago
$begingroup$
@Roman Did you try usingListCurvePathPlot? Because the data has such a small variation in theycoordinate,ListCurvePathPlotdoesn't work well. That's why I scaled the data and usedFindCurvePathto reorder the data, and then plotted the reordered data.
$endgroup$
– Carl Woll
46 mins ago
$begingroup$
Why not just the closely related
ListCurvePathPlot?$endgroup$
– Roman
1 hour ago
$begingroup$
Why not just the closely related
ListCurvePathPlot?$endgroup$
– Roman
1 hour ago
$begingroup$
@Roman Did you try using
ListCurvePathPlot? Because the data has such a small variation in the y coordinate, ListCurvePathPlot doesn't work well. That's why I scaled the data and used FindCurvePath to reorder the data, and then plotted the reordered data.$endgroup$
– Carl Woll
46 mins ago
$begingroup$
@Roman Did you try using
ListCurvePathPlot? Because the data has such a small variation in the y coordinate, ListCurvePathPlot doesn't work well. That's why I scaled the data and used FindCurvePath to reorder the data, and then plotted the reordered data.$endgroup$
– Carl Woll
46 mins ago
add a comment |
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1
$begingroup$
Try
FindShortestTour$endgroup$
– C. E.
3 hours ago
1
$begingroup$
Try something like
ListLinePlot[data[[Last@FindShortestTour@data]]]but it is not perfect$endgroup$
– J42161217
2 hours ago