Collect Fourier series termsCoefficientList for exponentials termsAssign Coefficients of Exponential SeriesConstruct Matrices from Coefficient of f[x] in Finite Fields?collect a multivariate polynomial, and simplify all coefficientsCollect terms with same-kind coefficients and factor exponential based on thatCollect terms in Fourier TransformExtracting coefficients from sumExtract terms containing a specific symbol from an expressionPlotting double seriesRearranging similar terms in an equation
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Collect Fourier series terms
CoefficientList for exponentials termsAssign Coefficients of Exponential SeriesConstruct Matrices from Coefficient of f[x] in Finite Fields?collect a multivariate polynomial, and simplify all coefficientsCollect terms with same-kind coefficients and factor exponential based on thatCollect terms in Fourier TransformExtracting coefficients from sumExtract terms containing a specific symbol from an expressionPlotting double seriesRearranging similar terms in an equation
$begingroup$
Is there a way to make mathematica automatically collect terms like $mathrmCos[n x]$ with $n=1,2,3...$?
I have a long expression coming out of a Fourier series where I see a lot of $Cos[x],Cos[2 x],Cos[3 x]$ and so on, but Simplify is very inefficient. I would like mathematica to automatically collect all coefficients of the various Cos[n x] without having to do it manually for each one of them.
coefficients
asked 4 hours ago
RiccardoRiccardo
405
$endgroup$
add a comment |
$begingroup$
Is there a way to make mathematica automatically collect terms like $mathrmCos[n x]$ with $n=1,2,3...$?
I have a long expression coming out of a Fourier series where I see a lot of $Cos[x],Cos[2 x],Cos[3 x]$ and so on, but Simplify is very inefficient. I would like mathematica to automatically collect all coefficients of the various Cos[n x] without having to do it manually for each one of them.
coefficients
asked 4 hours ago
RiccardoRiccardo
405
$endgroup$
$begingroup$
can you show your initial code, so we try to help!
$endgroup$
– Alrubaie
4 hours ago
add a comment |
$begingroup$
Is there a way to make mathematica automatically collect terms like $mathrmCos[n x]$ with $n=1,2,3...$?
I have a long expression coming out of a Fourier series where I see a lot of $Cos[x],Cos[2 x],Cos[3 x]$ and so on, but Simplify is very inefficient. I would like mathematica to automatically collect all coefficients of the various Cos[n x] without having to do it manually for each one of them.
coefficients
asked 4 hours ago
RiccardoRiccardo
405
$endgroup$
Is there a way to make mathematica automatically collect terms like $mathrmCos[n x]$ with $n=1,2,3...$?
I have a long expression coming out of a Fourier series where I see a lot of $Cos[x],Cos[2 x],Cos[3 x]$ and so on, but Simplify is very inefficient. I would like mathematica to automatically collect all coefficients of the various Cos[n x] without having to do it manually for each one of them.
coefficients
coefficients
asked 4 hours ago
RiccardoRiccardo
405
asked 4 hours ago
RiccardoRiccardo
405
asked 4 hours ago
RiccardoRiccardo
405
asked 4 hours ago
RiccardoRiccardo
405
asked 4 hours ago
RiccardoRiccardo
405
405
$begingroup$
can you show your initial code, so we try to help!
$endgroup$
– Alrubaie
4 hours ago
add a comment |
$begingroup$
can you show your initial code, so we try to help!
$endgroup$
– Alrubaie
4 hours ago
$begingroup$
can you show your initial code, so we try to help!
$endgroup$
– Alrubaie
4 hours ago
$begingroup$
can you show your initial code, so we try to help!
$endgroup$
– Alrubaie
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
is this what you are asking?
exp=3Cos[x]+5Cos[2x]+12Cos[3x];
Coefficient[exp,Cos[x #]]&/@Range@3
3, 5, 12
answered 4 hours ago
J42161217J42161217
4,238324
$endgroup$
$begingroup$
Yes, thanks this is it!
$endgroup$
– Riccardo
4 hours ago
$begingroup$
you are welcome!
$endgroup$
– J42161217
4 hours ago
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
is this what you are asking?
exp=3Cos[x]+5Cos[2x]+12Cos[3x];
Coefficient[exp,Cos[x #]]&/@Range@3
3, 5, 12
answered 4 hours ago
J42161217J42161217
4,238324
$endgroup$
$begingroup$
Yes, thanks this is it!
$endgroup$
– Riccardo
4 hours ago
$begingroup$
you are welcome!
$endgroup$
– J42161217
4 hours ago
add a comment |
$begingroup$
is this what you are asking?
exp=3Cos[x]+5Cos[2x]+12Cos[3x];
Coefficient[exp,Cos[x #]]&/@Range@3
3, 5, 12
answered 4 hours ago
J42161217J42161217
4,238324
$endgroup$
$begingroup$
Yes, thanks this is it!
$endgroup$
– Riccardo
4 hours ago
$begingroup$
you are welcome!
$endgroup$
– J42161217
4 hours ago
add a comment |
$begingroup$
is this what you are asking?
exp=3Cos[x]+5Cos[2x]+12Cos[3x];
Coefficient[exp,Cos[x #]]&/@Range@3
3, 5, 12
answered 4 hours ago
J42161217J42161217
4,238324
$endgroup$
is this what you are asking?
exp=3Cos[x]+5Cos[2x]+12Cos[3x];
Coefficient[exp,Cos[x #]]&/@Range@3
3, 5, 12
answered 4 hours ago
J42161217J42161217
4,238324
edited 4 hours ago
answered 4 hours ago
J42161217J42161217
4,238324
answered 4 hours ago
J42161217J42161217
4,238324
answered 4 hours ago
J42161217J42161217
4,238324
4,238324
$begingroup$
Yes, thanks this is it!
$endgroup$
– Riccardo
4 hours ago
$begingroup$
you are welcome!
$endgroup$
– J42161217
4 hours ago
add a comment |
$begingroup$
Yes, thanks this is it!
$endgroup$
– Riccardo
4 hours ago
$begingroup$
you are welcome!
$endgroup$
– J42161217
4 hours ago
$begingroup$
Yes, thanks this is it!
$endgroup$
– Riccardo
4 hours ago
$begingroup$
Yes, thanks this is it!
$endgroup$
– Riccardo
4 hours ago
$begingroup$
you are welcome!
$endgroup$
– J42161217
4 hours ago
$begingroup$
you are welcome!
$endgroup$
– J42161217
4 hours ago
add a comment |
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$begingroup$
can you show your initial code, so we try to help!
$endgroup$
– Alrubaie
4 hours ago